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ERoseM

  • 3 years ago

Check symmetry with respect to both axes and the origin of the graph of x^2y-x^2+4y=0

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  1. ERoseM
    • 3 years ago
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    Please help!

  2. psi9epsilon
    • 3 years ago
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    simple way is to replace x by -x and see if you get the same function then try replacing y by -y and see if you get the same function if thats the case it should be symm wrt to both axis or to either x if -x returns the same functin, or y if -y returns the same function

  3. ERoseM
    • 3 years ago
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    Thanks!

  4. psi9epsilon
    • 3 years ago
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    do you have the answers? lets verify the work

  5. ERoseM
    • 3 years ago
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    Okay, thank you. I thought I should factor out the x^2 does that make sense?

  6. psi9epsilon
    • 3 years ago
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    no, say you put x = -x then you will have (-x)^2y-(-x)^2+4y=0 which is same as original function as (-x)^2= x^2 so symettrical to x , then try for -y and it is not similar to original function

  7. ERoseM
    • 3 years ago
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    Oh! okay, thank you. That makes sense, I thought maybe factoring would make the answer seem easier but that is what i was taught. Thank you so much!

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