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Check symmetry with respect to both axes and the origin of the graph of x^2y-x^2+4y=0

Mathematics
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Please help!
simple way is to replace x by -x and see if you get the same function then try replacing y by -y and see if you get the same function if thats the case it should be symm wrt to both axis or to either x if -x returns the same functin, or y if -y returns the same function
Thanks!

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Other answers:

do you have the answers? lets verify the work
Okay, thank you. I thought I should factor out the x^2 does that make sense?
no, say you put x = -x then you will have (-x)^2y-(-x)^2+4y=0 which is same as original function as (-x)^2= x^2 so symettrical to x , then try for -y and it is not similar to original function
Oh! okay, thank you. That makes sense, I thought maybe factoring would make the answer seem easier but that is what i was taught. Thank you so much!

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