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\[\theta\] is step function

I can show you the work , it would be great if you can explain it

I get the n<=-1 part but not the n>-1

this is convultion

I know u(-k-1) is 1 for k= -inf to -1
u(x) is 0 for x<0, and 1 for x≥0
u(n-k) is 1 for k= -inf to +n

use convolution property

|dw:1347579756548:dw|

you can split up the basic sequence too, its way easier to do it

when n>-1 u(n-k) times u(-k-1) is zero for k≥ -1

clear as mud?

lol, I am reading all your posts over , will ask questions later

I get it how u(-t) is reflected across y axis

the picture is trying to show the two cases. If it helps, think logic, both steps have to be 1

still puzzling over it?

yeah, a lot of mental gymnastic, but thanks though

^that one did it, much more clear now