Quantcast

A community for students. Sign up today!

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

rainbow22

  • 2 years ago

find limit to infinity 4x sin (1/x) Answer is 4

  • This Question is Closed
  1. Algebraic!
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    multiply by (1/x)/(1/x)

  2. ivanmlerner
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    Or define y=1/x where y tends to 0, and you get the basic limit of (sin x)/x

  3. Algebraic!
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    "Or"

  4. rainbow22
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Can you please show me how to do it?

  5. ivanmlerner
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    that is it, there is nothing else, it is know that lim when y -> 0 of (sin x)/x is 1: look at the picture.|dw:1347580779959:dw|

  6. ivanmlerner
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    The arc lenght and the sin get praticaly equal, and in the limit they coincide, when you substitute what I said you get this limit, wich is 1, times 4.

  7. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Ask a Question
Find more explanations on OpenStudy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.