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  • 3 years ago

A=1/2h(a+b) solve for a

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  1. LolWolf
    • 3 years ago
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    So, we have: \[ \begin{align} A&=\frac{1}{2}h(a+b)\implies\\ 2A&=h(a+b)\implies\\ \frac{2A}{h}&=a+b\implies\\ \frac{2A}{h}-b&=a \end{align} \]

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