lgbasallote
  • lgbasallote
How many ways can you arrange four people in a row of four seats? is this 4P4?
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
No, its 4!
anonymous
  • anonymous
4!= 4*3*2*1
anonymous
  • anonymous
There is only one way

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
But If u are asking for different arrangement then its 4!
lgbasallote
  • lgbasallote
\[4 P 4 = \frac{4!}{(4-4)!} \implies \frac {4!}{0!} \implies 4!\] @GOODMAN
anonymous
  • anonymous
So why go through all the trouble?
anonymous
  • anonymous
Yep, \(_4P_4\) is correct.
lgbasallote
  • lgbasallote
because of this next question im about to ask
lgbasallote
  • lgbasallote
what about for arranging 4 people in 5 seats? is that 5P4? and arranging 5 people in 4 seats is also 5P4?
anonymous
  • anonymous
Actually both will be 5!
anonymous
  • anonymous
For first case it would be 5*4!=5! For second case it would be 5*4*3*2 = 5!
anonymous
  • anonymous
If u are taking about arrangement
lgbasallote
  • lgbasallote
....so they are both 5P4?
anonymous
  • anonymous
Yep
anonymous
  • anonymous
I think so
anonymous
  • anonymous
Yes to both responses. To check we can show that: 4 people in 5 seats: We can always choose a single person whom is not in a seat, and there are 5 ways to do this, while the remaining 4 get a seat, thus: \(5\cdot_4P_4= _5P_4\), while for the latter, we have, simply \(_5P_4\) as the definition of "permute".
lgbasallote
  • lgbasallote
i think im getting the hang of this
anonymous
  • anonymous
Sounds good
karatechopper
  • karatechopper
So...like 16?

Looking for something else?

Not the answer you are looking for? Search for more explanations.