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lgbasallote
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How many ways can you arrange four people in a row of four seats?
is this 4P4?
 one year ago
 one year ago
lgbasallote Group Title
How many ways can you arrange four people in a row of four seats? is this 4P4?
 one year ago
 one year ago

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GOODMAN Group TitleBest ResponseYou've already chosen the best response.0
No, its 4!
 one year ago

GOODMAN Group TitleBest ResponseYou've already chosen the best response.0
4!= 4*3*2*1
 one year ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.2
There is only one way
 one year ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.2
But If u are asking for different arrangement then its 4!
 one year ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
\[4 P 4 = \frac{4!}{(44)!} \implies \frac {4!}{0!} \implies 4!\] @GOODMAN
 one year ago

GOODMAN Group TitleBest ResponseYou've already chosen the best response.0
So why go through all the trouble?
 one year ago

LolWolf Group TitleBest ResponseYou've already chosen the best response.2
Yep, \(_4P_4\) is correct.
 one year ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
because of this next question im about to ask
 one year ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
what about for arranging 4 people in 5 seats? is that 5P4? and arranging 5 people in 4 seats is also 5P4?
 one year ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.2
Actually both will be 5!
 one year ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.2
For first case it would be 5*4!=5! For second case it would be 5*4*3*2 = 5!
 one year ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.2
If u are taking about arrangement
 one year ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
....so they are both 5P4?
 one year ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.2
I think so
 one year ago

LolWolf Group TitleBest ResponseYou've already chosen the best response.2
Yes to both responses. To check we can show that: 4 people in 5 seats: We can always choose a single person whom is not in a seat, and there are 5 ways to do this, while the remaining 4 get a seat, thus: \(5\cdot_4P_4= _5P_4\), while for the latter, we have, simply \(_5P_4\) as the definition of "permute".
 one year ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
i think im getting the hang of this
 one year ago

LolWolf Group TitleBest ResponseYou've already chosen the best response.2
Sounds good
 one year ago

karatechopper Group TitleBest ResponseYou've already chosen the best response.0
So...like 16?
 one year ago
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