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 2 years ago
How many ways can you arrange four people in a row of four seats?
is this 4P4?
 2 years ago
How many ways can you arrange four people in a row of four seats? is this 4P4?

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sauravshakya
 2 years ago
Best ResponseYou've already chosen the best response.2There is only one way

sauravshakya
 2 years ago
Best ResponseYou've already chosen the best response.2But If u are asking for different arrangement then its 4!

lgbasallote
 2 years ago
Best ResponseYou've already chosen the best response.0\[4 P 4 = \frac{4!}{(44)!} \implies \frac {4!}{0!} \implies 4!\] @GOODMAN

GOODMAN
 2 years ago
Best ResponseYou've already chosen the best response.0So why go through all the trouble?

LolWolf
 2 years ago
Best ResponseYou've already chosen the best response.2Yep, \(_4P_4\) is correct.

lgbasallote
 2 years ago
Best ResponseYou've already chosen the best response.0because of this next question im about to ask

lgbasallote
 2 years ago
Best ResponseYou've already chosen the best response.0what about for arranging 4 people in 5 seats? is that 5P4? and arranging 5 people in 4 seats is also 5P4?

sauravshakya
 2 years ago
Best ResponseYou've already chosen the best response.2Actually both will be 5!

sauravshakya
 2 years ago
Best ResponseYou've already chosen the best response.2For first case it would be 5*4!=5! For second case it would be 5*4*3*2 = 5!

sauravshakya
 2 years ago
Best ResponseYou've already chosen the best response.2If u are taking about arrangement

lgbasallote
 2 years ago
Best ResponseYou've already chosen the best response.0....so they are both 5P4?

LolWolf
 2 years ago
Best ResponseYou've already chosen the best response.2Yes to both responses. To check we can show that: 4 people in 5 seats: We can always choose a single person whom is not in a seat, and there are 5 ways to do this, while the remaining 4 get a seat, thus: \(5\cdot_4P_4= _5P_4\), while for the latter, we have, simply \(_5P_4\) as the definition of "permute".

lgbasallote
 2 years ago
Best ResponseYou've already chosen the best response.0i think im getting the hang of this
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