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lgbasallote
 3 years ago
Three cards are given to you from a wellshuffled deck of cards. What is the probability that you get all 3 cards from the same suit?
lgbasallote
 3 years ago
Three cards are given to you from a wellshuffled deck of cards. What is the probability that you get all 3 cards from the same suit?

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satellite73
 3 years ago
Best ResponseYou've already chosen the best response.0thirteen choose three over fifty two choose three

lgbasallote
 3 years ago
Best ResponseYou've already chosen the best response.0is this \[\frac 1{52 C3}\]

KingGeorge
 3 years ago
Best ResponseYou've already chosen the best response.1Try the method I was talking about a little earlier.

KingGeorge
 3 years ago
Best ResponseYou've already chosen the best response.1You first need to find the possible ways you can choose three cards from the same suit, and then divide by all the possible three card hands. So you have Construction: Choices: 1. Choose a suit \(\binom41\) and then 2. Choose a 3 card set from 13 \(\binom{13}{3}\) So there are \[\binom41\cdot\binom{13}{3}\]3card hands where all the cards are from the same suit.

lgbasallote
 3 years ago
Best ResponseYou've already chosen the best response.0so the probability would be \[\frac 1{4 C 1 \times 13 C 3}\]

KingGeorge
 3 years ago
Best ResponseYou've already chosen the best response.1Now we need to find all 3 card hands total. This is just \(\binom{52}{3}\) (it's a one step process with how I was doing it before). Thus, your probability would be \[\Large P=\frac{\binom{4}{1}\cdot\binom{13}{3}}{\binom{52}{3}}\]

lgbasallote
 3 years ago
Best ResponseYou've already chosen the best response.0probability is.... the possible events over the total right?

KingGeorge
 3 years ago
Best ResponseYou've already chosen the best response.1We have to divide by the total number of hands to find probability.

lgbasallote
 3 years ago
Best ResponseYou've already chosen the best response.0oh. i get the logic now
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