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thirteen choose three over fifty two choose three

times four

is this \[\frac 1{52 C3}\]

Try the method I was talking about a little earlier.

so the probability would be \[\frac 1{4 C 1 \times 13 C 3}\]

probability is.... the possible events over the total right?

We have to divide by the total number of hands to find probability.

Right.

oh. i get the logic now

thanks

You're welcome.