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lgbasallote
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Three cards are given to you from a wellshuffled deck of cards. What is the probability that you get all 3 cards from the same suit?
 one year ago
 one year ago
lgbasallote Group Title
Three cards are given to you from a wellshuffled deck of cards. What is the probability that you get all 3 cards from the same suit?
 one year ago
 one year ago

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satellite73 Group TitleBest ResponseYou've already chosen the best response.0
thirteen choose three over fifty two choose three
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.0
times four
 one year ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
is this \[\frac 1{52 C3}\]
 one year ago

KingGeorge Group TitleBest ResponseYou've already chosen the best response.1
Try the method I was talking about a little earlier.
 one year ago

KingGeorge Group TitleBest ResponseYou've already chosen the best response.1
You first need to find the possible ways you can choose three cards from the same suit, and then divide by all the possible three card hands. So you have Construction: Choices: 1. Choose a suit \(\binom41\) and then 2. Choose a 3 card set from 13 \(\binom{13}{3}\) So there are \[\binom41\cdot\binom{13}{3}\]3card hands where all the cards are from the same suit.
 one year ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
so the probability would be \[\frac 1{4 C 1 \times 13 C 3}\]
 one year ago

KingGeorge Group TitleBest ResponseYou've already chosen the best response.1
Now we need to find all 3 card hands total. This is just \(\binom{52}{3}\) (it's a one step process with how I was doing it before). Thus, your probability would be \[\Large P=\frac{\binom{4}{1}\cdot\binom{13}{3}}{\binom{52}{3}}\]
 one year ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
probability is.... the possible events over the total right?
 one year ago

KingGeorge Group TitleBest ResponseYou've already chosen the best response.1
We have to divide by the total number of hands to find probability.
 one year ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
oh. i get the logic now
 one year ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
thanks
 one year ago

KingGeorge Group TitleBest ResponseYou've already chosen the best response.1
You're welcome.
 one year ago
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