3psilon
  • 3psilon
Trig limits help?
Mathematics
schrodinger
  • schrodinger
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3psilon
  • 3psilon
\[\lim_{\theta \rightarrow \frac{ 7\pi }{ 6 }} \frac{ \sin \theta }{ 6 \theta } \]
3psilon
  • 3psilon
It's been a long time since precal. Can somebody refresh me?
anonymous
  • anonymous
teta --> ? i dont see very well

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3psilon
  • 3psilon
7pi /6 @tanjung
anonymous
  • anonymous
You can simply plug in \(\theta=\frac{7\pi}{6}\)
3psilon
  • 3psilon
But I'm getting 3/7pi and the book is getting -1/14pi
anonymous
  • anonymous
It's \(-\frac{1}{14}\) since: \[ \sin\frac{7\pi}{6}=-\sin\frac{\pi}{6}=-\frac{1}{2} \]Thus: \[ 6\left(\frac{7\pi}{6}\right)=7\pi \]And: \[ \frac{-\frac{1}{2}}{7\pi}=-\frac{1}{14\pi} \]
3psilon
  • 3psilon
So you do it as radians regardless it says theta?
anonymous
  • anonymous
Yep
anonymous
  • anonymous
\(\theta\) just means "angle".
3psilon
  • 3psilon
Yeah I just caught my mistake -_- that was the last question of the day @LolWolf won't bother you anymore. Thanks
anonymous
  • anonymous
It's cool, and bother me? That's what I'm here for, haha... and no problem.
anonymous
  • anonymous
sin 7pi/6 = sin 210 degree = -1/2 6(7pi/6) = 7pi if u divided both, get the anwer is (-1/2)/7pi = -1/14pi
3psilon
  • 3psilon
Thanks @tanjung I got it now! :)
anonymous
  • anonymous
yup..wellcome :)

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