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3psilon Group TitleBest ResponseYou've already chosen the best response.0
\[\lim_{\theta \rightarrow \frac{ 7\pi }{ 6 }} \frac{ \sin \theta }{ 6 \theta } \]
 2 years ago

3psilon Group TitleBest ResponseYou've already chosen the best response.0
It's been a long time since precal. Can somebody refresh me?
 2 years ago

tanjung Group TitleBest ResponseYou've already chosen the best response.0
teta > ? i dont see very well
 2 years ago

3psilon Group TitleBest ResponseYou've already chosen the best response.0
7pi /6 @tanjung
 2 years ago

LolWolf Group TitleBest ResponseYou've already chosen the best response.1
You can simply plug in \(\theta=\frac{7\pi}{6}\)
 2 years ago

3psilon Group TitleBest ResponseYou've already chosen the best response.0
But I'm getting 3/7pi and the book is getting 1/14pi
 2 years ago

LolWolf Group TitleBest ResponseYou've already chosen the best response.1
It's \(\frac{1}{14}\) since: \[ \sin\frac{7\pi}{6}=\sin\frac{\pi}{6}=\frac{1}{2} \]Thus: \[ 6\left(\frac{7\pi}{6}\right)=7\pi \]And: \[ \frac{\frac{1}{2}}{7\pi}=\frac{1}{14\pi} \]
 2 years ago

3psilon Group TitleBest ResponseYou've already chosen the best response.0
So you do it as radians regardless it says theta?
 2 years ago

LolWolf Group TitleBest ResponseYou've already chosen the best response.1
\(\theta\) just means "angle".
 2 years ago

3psilon Group TitleBest ResponseYou've already chosen the best response.0
Yeah I just caught my mistake _ that was the last question of the day @LolWolf won't bother you anymore. Thanks
 2 years ago

LolWolf Group TitleBest ResponseYou've already chosen the best response.1
It's cool, and bother me? That's what I'm here for, haha... and no problem.
 2 years ago

tanjung Group TitleBest ResponseYou've already chosen the best response.0
sin 7pi/6 = sin 210 degree = 1/2 6(7pi/6) = 7pi if u divided both, get the anwer is (1/2)/7pi = 1/14pi
 2 years ago

3psilon Group TitleBest ResponseYou've already chosen the best response.0
Thanks @tanjung I got it now! :)
 2 years ago

tanjung Group TitleBest ResponseYou've already chosen the best response.0
yup..wellcome :)
 2 years ago
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