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3psilon

  • 3 years ago

Trig limits help?

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  1. 3psilon
    • 3 years ago
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    \[\lim_{\theta \rightarrow \frac{ 7\pi }{ 6 }} \frac{ \sin \theta }{ 6 \theta } \]

  2. 3psilon
    • 3 years ago
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    It's been a long time since precal. Can somebody refresh me?

  3. tanjung
    • 3 years ago
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    teta --> ? i dont see very well

  4. 3psilon
    • 3 years ago
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    7pi /6 @tanjung

  5. LolWolf
    • 3 years ago
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    You can simply plug in \(\theta=\frac{7\pi}{6}\)

  6. 3psilon
    • 3 years ago
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    But I'm getting 3/7pi and the book is getting -1/14pi

  7. LolWolf
    • 3 years ago
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    It's \(-\frac{1}{14}\) since: \[ \sin\frac{7\pi}{6}=-\sin\frac{\pi}{6}=-\frac{1}{2} \]Thus: \[ 6\left(\frac{7\pi}{6}\right)=7\pi \]And: \[ \frac{-\frac{1}{2}}{7\pi}=-\frac{1}{14\pi} \]

  8. 3psilon
    • 3 years ago
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    So you do it as radians regardless it says theta?

  9. LolWolf
    • 3 years ago
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    Yep

  10. LolWolf
    • 3 years ago
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    \(\theta\) just means "angle".

  11. 3psilon
    • 3 years ago
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    Yeah I just caught my mistake -_- that was the last question of the day @LolWolf won't bother you anymore. Thanks

  12. LolWolf
    • 3 years ago
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    It's cool, and bother me? That's what I'm here for, haha... and no problem.

  13. tanjung
    • 3 years ago
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    sin 7pi/6 = sin 210 degree = -1/2 6(7pi/6) = 7pi if u divided both, get the anwer is (-1/2)/7pi = -1/14pi

  14. 3psilon
    • 3 years ago
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    Thanks @tanjung I got it now! :)

  15. tanjung
    • 3 years ago
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    yup..wellcome :)

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