3psilon
Trig limits help?



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3psilon
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\[\lim_{\theta \rightarrow \frac{ 7\pi }{ 6 }} \frac{ \sin \theta }{ 6 \theta } \]

3psilon
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It's been a long time since precal. Can somebody refresh me?

tanjung
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teta > ? i dont see very well

3psilon
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7pi /6 @tanjung

LolWolf
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You can simply plug in \(\theta=\frac{7\pi}{6}\)

3psilon
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But I'm getting 3/7pi and the book is getting 1/14pi

LolWolf
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It's \(\frac{1}{14}\) since:
\[
\sin\frac{7\pi}{6}=\sin\frac{\pi}{6}=\frac{1}{2}
\]Thus:
\[
6\left(\frac{7\pi}{6}\right)=7\pi
\]And:
\[
\frac{\frac{1}{2}}{7\pi}=\frac{1}{14\pi}
\]

3psilon
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So you do it as radians regardless it says theta?

LolWolf
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Yep

LolWolf
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\(\theta\) just means "angle".

3psilon
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Yeah I just caught my mistake _ that was the last question of the day @LolWolf won't bother you anymore. Thanks

LolWolf
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It's cool, and bother me? That's what I'm here for, haha... and no problem.

tanjung
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sin 7pi/6 = sin 210 degree = 1/2
6(7pi/6) = 7pi
if u divided both, get the anwer is
(1/2)/7pi = 1/14pi

3psilon
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Thanks @tanjung I got it now! :)

tanjung
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yup..wellcome :)