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mystique2626
Group Title
Use the method of substitution to solve the system of linear equations
8x+4y=8/5
y=5x1
 one year ago
 one year ago
mystique2626 Group Title
Use the method of substitution to solve the system of linear equations 8x+4y=8/5 y=5x1
 one year ago
 one year ago

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itsmichi95 Group TitleBest ResponseYou've already chosen the best response.0
plug in the value of Y into the equation, 8x+4y=8/5 instead of 4y you would put in the value of Y like this: 8x+4(5x1)=8/5 then just solve(: do you get that or you need more help?
 one year ago

hehsy5sy5 Group TitleBest ResponseYou've already chosen the best response.0
Substitution means you can plug in one value of y for another. they made it easy for you by singling out the y, by y=5x1 Plug y=5x1 into the other equation, 8x+4(5x1)=8/5. From there you can single out the value of x, and plug x back in to get y.
 one year ago

mystique2626 Group TitleBest ResponseYou've already chosen the best response.0
okay what i have so far is 28x=9/5 is that right so far?
 one year ago

hehsy5sy5 Group TitleBest ResponseYou've already chosen the best response.0
I don't understand how you got 28x=9/5 You should make sure to factor out correctly. 4(5x1)= 20x4. 20x4+8x= 28x4=8/5. 28x= 8/5 +4. From there it should be easy to get the x. After getting x, plug into the original equations(hint, pick the easier one) and voila you got y.
 one year ago

mystique2626 Group TitleBest ResponseYou've already chosen the best response.0
does x =1?
 one year ago

mystique2626 Group TitleBest ResponseYou've already chosen the best response.0
oops i messed that up i think
 one year ago

mystique2626 Group TitleBest ResponseYou've already chosen the best response.0
okay so 28x=8/5+4. so do i combine 8/5 and 4?
 one year ago
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