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mystique2626
Group Title
Use the method of substitution to solve the system of linear equations
8x+4y=8/5
y=5x1
 2 years ago
 2 years ago
mystique2626 Group Title
Use the method of substitution to solve the system of linear equations 8x+4y=8/5 y=5x1
 2 years ago
 2 years ago

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itsmichi95 Group TitleBest ResponseYou've already chosen the best response.0
plug in the value of Y into the equation, 8x+4y=8/5 instead of 4y you would put in the value of Y like this: 8x+4(5x1)=8/5 then just solve(: do you get that or you need more help?
 2 years ago

hehsy5sy5 Group TitleBest ResponseYou've already chosen the best response.0
Substitution means you can plug in one value of y for another. they made it easy for you by singling out the y, by y=5x1 Plug y=5x1 into the other equation, 8x+4(5x1)=8/5. From there you can single out the value of x, and plug x back in to get y.
 2 years ago

mystique2626 Group TitleBest ResponseYou've already chosen the best response.0
okay what i have so far is 28x=9/5 is that right so far?
 2 years ago

hehsy5sy5 Group TitleBest ResponseYou've already chosen the best response.0
I don't understand how you got 28x=9/5 You should make sure to factor out correctly. 4(5x1)= 20x4. 20x4+8x= 28x4=8/5. 28x= 8/5 +4. From there it should be easy to get the x. After getting x, plug into the original equations(hint, pick the easier one) and voila you got y.
 2 years ago

mystique2626 Group TitleBest ResponseYou've already chosen the best response.0
does x =1?
 2 years ago

mystique2626 Group TitleBest ResponseYou've already chosen the best response.0
oops i messed that up i think
 2 years ago

mystique2626 Group TitleBest ResponseYou've already chosen the best response.0
okay so 28x=8/5+4. so do i combine 8/5 and 4?
 2 years ago
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