Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing
2. A company produces antidote injection vials. Suppose the probability to have a defective vial is 1 per 5000 vials:
(a) If 5 vials are randomly selected,
i. what is the average number of vials you expect to be defective?
ii. what is the probability that at least one of them is defective?
(b) If 10,000 vials are randomly selected, (think of this as an 'area of opportunity')
i. what is the average number of vials you expect to be defective?
ii. what is the probability that at least one of them is defective?
 one year ago
 one year ago
2. A company produces antidote injection vials. Suppose the probability to have a defective vial is 1 per 5000 vials: (a) If 5 vials are randomly selected, i. what is the average number of vials you expect to be defective? ii. what is the probability that at least one of them is defective? (b) If 10,000 vials are randomly selected, (think of this as an 'area of opportunity') i. what is the average number of vials you expect to be defective? ii. what is the probability that at least one of them is defective?
 one year ago
 one year ago

This Question is Closed

sauravshakyaBest ResponseYou've already chosen the best response.0
FOR (a) its Binomial distribution FOR (b) its NORMAL distribution
 one year ago

allankBest ResponseYou've already chosen the best response.0
Well, you could think about it logically: The probability to have a defective vial is 1 per 5000 vials. Thus the probability that any given vial picked is defective is 1/5000. a) If 5 vials are selected, the total probability of being defective is 5*1/5000=1/1000. Thus we expect 1/1000 of the 5 vials to be defective. Thus i) 1/1000
 one year ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.