A community for students.
Here's the question you clicked on:
 0 viewing
Chena804
 3 years ago
2. A company produces antidote injection vials. Suppose the probability to have a defective vial is 1 per 5000 vials:
(a) If 5 vials are randomly selected,
i. what is the average number of vials you expect to be defective?
ii. what is the probability that at least one of them is defective?
(b) If 10,000 vials are randomly selected, (think of this as an 'area of opportunity')
i. what is the average number of vials you expect to be defective?
ii. what is the probability that at least one of them is defective?
Chena804
 3 years ago
2. A company produces antidote injection vials. Suppose the probability to have a defective vial is 1 per 5000 vials: (a) If 5 vials are randomly selected, i. what is the average number of vials you expect to be defective? ii. what is the probability that at least one of them is defective? (b) If 10,000 vials are randomly selected, (think of this as an 'area of opportunity') i. what is the average number of vials you expect to be defective? ii. what is the probability that at least one of them is defective?

This Question is Closed

sauravshakya
 3 years ago
Best ResponseYou've already chosen the best response.0FOR (a) its Binomial distribution FOR (b) its NORMAL distribution

allank
 3 years ago
Best ResponseYou've already chosen the best response.0Well, you could think about it logically: The probability to have a defective vial is 1 per 5000 vials. Thus the probability that any given vial picked is defective is 1/5000. a) If 5 vials are selected, the total probability of being defective is 5*1/5000=1/1000. Thus we expect 1/1000 of the 5 vials to be defective. Thus i) 1/1000
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.