Quantcast

A community for students. Sign up today!

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

cuzzin

  • 2 years ago

Let f(x)=(2x^2-x). Give f '(1).

  • This Question is Closed
  1. cuzzin
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    I'm a little stumped on this "Give f '(1) problems.

  2. ParthKohli
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    First, find the derivative. What is \(f'(x)\)?

  3. cuzzin
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    1?

  4. ParthKohli
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    No, no. It'd be\[f'(x) = {d \over dx}2x^2 - x\]Do you know what derivative is?

  5. febylailani
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Let f(x)=(2x^2-x). Give f '(1). f'(x) = 4x f'(1) = 4(1) = 4 . am i right?

  6. cuzzin
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Well we are just starting the chapter on derivatives, so I'm still figuring them out. Mostly we've been dealing with finding the slope of tangent and normal lines.

  7. ParthKohli
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    @febylailani I should point out that,\[f'(x) = 4x - 1\]

  8. akash809
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    3

  9. ParthKohli
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    @cuzzin That includes differentiation too!

  10. ParthKohli
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    \[f'(x) = 4x - 1\]\[f'(1) = 4(1) - 1\]

  11. Omniscience
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    I think you should write it as: \[\frac{d}{dx} \left(2x^{2}-x\right) or \frac{d}{dx} 2x^2-\frac{d}{dx} x\] Or people would get confused,which was evident :)

  12. akash809
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    why to make things more complicated

  13. ParthKohli
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    @Omniscience is pretty well till now, and then the power rule!:)

  14. febylailani
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    ah!! yup! sorry i forgot. careless -_- aaaaaccckkkkk

  15. cuzzin
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Ok, where does the (4x-1) come from?

  16. febylailani
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    from differential.

  17. febylailani
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    but differential is the short way. before that, there's limit. the formula is a.n.x^(n-1). i.e. f(x) = 2x^3 ; a=2 ; n = 3 so, f'(x) = 2.3.x^(3-1) = 6x^2 cmiiw

  18. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Ask a Question
Find more explanations on OpenStudy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.