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I'm a little stumped on this "Give f '(1) problems.

First, find the derivative. What is \(f'(x)\)?

1?

No, no. It'd be\[f'(x) = {d \over dx}2x^2 - x\]Do you know what derivative is?

Let f(x)=(2x^2-x). Give f '(1).
f'(x) = 4x
f'(1) = 4(1) = 4 . am i right?

@febylailani I should point out that,\[f'(x) = 4x - 1\]

@cuzzin That includes differentiation too!

\[f'(x) = 4x - 1\]\[f'(1) = 4(1) - 1\]

why to make things more complicated

@Omniscience is pretty well till now, and then the power rule!:)

ah!! yup! sorry i forgot. careless -_- aaaaaccckkkkk

Ok, where does the (4x-1) come from?

from differential.