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psk981

  • 2 years ago

dy/dx= 3x^3y Solve the differential equation. Write the answer as an explicit solution (i.e. solve for the dependent variable).

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  1. psk981
    • 2 years ago
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    it is \[3x ^{3}*y\]

  2. akash809
    • 2 years ago
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    u sure abt the power 3x^3y..i dont think i hv seen something like that before

  3. ParthKohli
    • 2 years ago
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    \[{dy \over dx} = 3x^{\large3}y\]Actually, that's the question for everyone's clarification.

  4. akash809
    • 2 years ago
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    ans is ln(y)= 3x^4/4 +c

  5. akash809
    • 2 years ago
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    ryt

  6. Algebraic!
    • 2 years ago
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    \[\frac{ dy }{ y} = { x ^{3}dx}\]

  7. akash809
    • 2 years ago
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    yes integrate that and u get what i posted

  8. akash809
    • 2 years ago
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    give me a medal psk if the ans is ryt :)'

  9. Algebraic!
    • 2 years ago
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    http://openstudy.com/code-of-conduct

  10. akash809
    • 2 years ago
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    r u moderator

  11. Algebraic!
    • 2 years ago
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    no u?

  12. Omniscience
    • 2 years ago
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    \[\frac{dy}{dx} =3x^{3} y => \frac{dy}{y} =3x^3dx => \int\limits\frac{dy}{y} =\int\limits3x^{3}dx => \ln(y)=\frac{3x^{4}}{4} +C\] i think you have to find the analytical solution next

  13. febylailani
    • 2 years ago
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    dy/dx= 3x^(3)*y 3.3x2. how about y??

  14. psk981
    • 2 years ago
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    then if i take ln of both sides i should get the whole right side in exponent form??

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