anonymous
  • anonymous
Calculate the # of moles present. 521 mg of germanium
Chemistry
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anonymous
  • anonymous
Calculate the # of moles present. 521 mg of germanium
Chemistry
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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.Sam.
  • .Sam.
Start by finding the g/mol of germanium using the periodic table, http://www.ptable.com/ Looks like its 72.6g/mol. So, you want to find the number of moles, you can use the fraction method. \[521mg =5.21 \times 10 ^{-1} \text{ g of germanium}\] \[5.21 \times 10 ^{-1} \text{ g of germanium} \times \frac{\text{1 mole of germanium}}{\text{72.6 g of germanium}}\] \[5.21 \times 10 ^{-1} \cancel{\text{g of germanium}} \times \frac{\text{1 mole of germanium}}{72.6 \cancel{\text{ g of germanium}}}=7.17 \times 10^{-3} \text{ moles of germanium}\]

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