A community for students.
Here's the question you clicked on:
 0 viewing
Chiomatn93
 3 years ago
Calculate the # of moles present.
521 mg of germanium
Chiomatn93
 3 years ago
Calculate the # of moles present. 521 mg of germanium

This Question is Closed

.Sam.
 3 years ago
Best ResponseYou've already chosen the best response.0Start by finding the g/mol of germanium using the periodic table, http://www.ptable.com/ Looks like its 72.6g/mol. So, you want to find the number of moles, you can use the fraction method. \[521mg =5.21 \times 10 ^{1} \text{ g of germanium}\] \[5.21 \times 10 ^{1} \text{ g of germanium} \times \frac{\text{1 mole of germanium}}{\text{72.6 g of germanium}}\] \[5.21 \times 10 ^{1} \cancel{\text{g of germanium}} \times \frac{\text{1 mole of germanium}}{72.6 \cancel{\text{ g of germanium}}}=7.17 \times 10^{3} \text{ moles of germanium}\]
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.