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anonymous
 3 years ago
What is the approximate value of the function at x = 3?
anonymous
 3 years ago
What is the approximate value of the function at x = 3?

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0How high is the line (measured using the yaxis) over the horizontal point (x=) 3?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0He's saying look above x=3.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1347647720757:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0It's slightly higher than 1.

theEric
 3 years ago
Best ResponseYou've already chosen the best response.1Somewhere around there! It looks closest to the y=1 line. To me it looks like 1.2 or somewhere around 1.2, but your teacher may want you to stick to the drawn lines for accuracy. I don't kno! But it is definately about 1. There's no way to konw exactly what it is without knowing how each horizontal value (such as 3) determines the vertical value (like the one we are trying to estimate).

theEric
 3 years ago
Best ResponseYou've already chosen the best response.1CliffSedge made a good point, saying that it's greater than 1. It's true to say that this mystery value is between 1 and 2.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so is there a definite answer i can give?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0theEric's guess of 1.2 is pretty good. I really doubt it's higher than 1.3 or 1.4.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0The whole point of an approximation is that you DON'T give a definite answer. Guess.

theEric
 3 years ago
Best ResponseYou've already chosen the best response.1Has your teacher gave you any guidelines for estimating? and thank you!

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Really, I think you're over complicating. It looks sort of like it could be in the vicinity of 1.2 ish. Good enough.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0There is a definite (exact) answer to give if you had the equation. You can make a good guess and be definite about how uncertain you are.

theEric
 3 years ago
Best ResponseYou've already chosen the best response.1Sometimes teachers will want you to estimate a certain way, so that there is only one answer, and that might be the case here. So, in that sense there may be a definate answer where there is no definate value. I'd say just guess about 1.2! That would be what all my teachers would've liked, I think!

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0It looks like the equation would be \[y=\frac{1}{(x3)}+1\] If you want to get it exactly.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0One of the important things about estimation is that you don't want to claim more precision than you actually have. In this situation, with that scale, you can't really get any better than to estimate to ±½ or ±¼ at best. You can definitely do better than rounding to the nearest whole number, so go out to the tenths place and you'll be fine.

theEric
 3 years ago
Best ResponseYou've already chosen the best response.1CliffSedge proposed an equation that seems right! Notably, the asemptote is at x=2, and his formula yields y=2 at x=2 which looks pretty exact in the picture.

theEric
 3 years ago
Best ResponseYou've already chosen the best response.1Again, CliffSedge made a great point: about accuracy this time!
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