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You have a 1.0 μF, 2.0 μF and 3.0 μF capacitors. What
capacitances can you get by connecting them?
 one year ago
 one year ago
You have a 1.0 μF, 2.0 μF and 3.0 μF capacitors. What capacitances can you get by connecting them?
 one year ago
 one year ago

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Carl_PhamBest ResponseYou've already chosen the best response.0
\[(1.0 + 2.0 + 3.0) \mu{\rm F}\] \[\left(\frac{1.0 + 2.0}{2} + 3.0\right)\mu{\rm F}\] \[\left(\frac{1.0 + 3.0}{2} + 2.0\right)\mu{\rm F}\] \[\left(\frac{2.0 + 3.0}{2} + 1.0\right)\mu{\rm F}\] \[\left(\frac{1.0 + 2.0 + 3.0}{3} \right)\mu{\rm F}\]
 one year ago

NoelGrecoBest ResponseYou've already chosen the best response.1
Not quite Carl. The first one is correct for all three caps in parallel. The correct formula for capacitors in series is:\[\frac{ 1 }{ C _{Eq} }= \frac{ 1 }{ C _{1} }+\frac{ 1 }{ C _{2} }+\frac{ 1 }{ C _{3} }...\] which reduces to: \[C _{Eq}=\frac{ C _{1}C _{2} }{C _{1}+C _{2} }\] for two capacitors in series.
 one year ago

Carl_PhamBest ResponseYou've already chosen the best response.0
RIght you are. For some reason I had a braino and thought we were dealing with resisters. Substitute the inverses for the numbers in all the equations, and invert at the end.
 one year ago
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