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magepker728 Group Title

x^2-6=0 why isnt it (x+2) (x-3)=0 just need to know why

  • 2 years ago
  • 2 years ago

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  1. hartnn Group Title
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    because 3*3=9 and not 6

    • 2 years ago
  2. hartnn Group Title
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    x^2-9 = x^2-3^2 = (x+3)(x-3)

    • 2 years ago
  3. hartnn Group Title
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    x^2-6 = x^2-9+3 = (x+3)(x-3)+3

    • 2 years ago
  4. magepker728 Group Title
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    typo its suppose to be (x-3) (x+2)

    • 2 years ago
  5. hartnn Group Title
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    ohh, (x-3)(x+2) = x^2 -3x+2x -6 =x^2 -x -6 and not x^2 -6

    • 2 years ago
  6. magepker728 Group Title
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    if factored is it (x-3) (x+2) or square root +-6?

    • 2 years ago
  7. hartnn Group Title
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    roots are \(\large \pm \sqrt6\) factors are \((x+\sqrt6)(x-\sqrt6) \)

    • 2 years ago
  8. magepker728 Group Title
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    but it is not (x-3) (x+2)

    • 2 years ago
  9. hartnn Group Title
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    exatly! its not because (x-3)(x+2) = x^2-x-6

    • 2 years ago
  10. magepker728 Group Title
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    ooh i see

    • 2 years ago
  11. akash809 Group Title
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    (x-3) (x-2)= x^2-2x-3x+6=x^2-5x+6...so u got an extra 5x

    • 2 years ago
  12. hartnn Group Title
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    ask if still any doubts.

    • 2 years ago
  13. magepker728 Group Title
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    so when ever it is not a perfect square, i have to to take the square root of both side?

    • 2 years ago
  14. CliffSedge Group Title
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    You have to take the square root regardless.

    • 2 years ago
  15. hartnn Group Title
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    whenever ? when its in the form of x^2 - a^2 = 0

    • 2 years ago
  16. hartnn Group Title
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    then shift a^2 to other side and take square root.

    • 2 years ago
  17. magepker728 Group Title
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    k thanks

    • 2 years ago
  18. hartnn Group Title
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    welcome :)

    • 2 years ago
  19. febylailani Group Title
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    bcs u hv 1 exttra x :)

    • 2 years ago
  20. magepker728 Group Title
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    :D

    • 2 years ago
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