magepker728
x^26=0
why isnt it (x+2) (x3)=0 just need to know why



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hartnn
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because 3*3=9 and not 6

hartnn
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x^29 = x^23^2 = (x+3)(x3)

hartnn
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x^26 = x^29+3 = (x+3)(x3)+3

magepker728
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typo its suppose to be (x3) (x+2)

hartnn
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ohh,
(x3)(x+2) = x^2 3x+2x 6
=x^2 x 6
and not x^2 6

magepker728
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if factored is it (x3) (x+2) or square root +6?

hartnn
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roots are \(\large \pm \sqrt6\)
factors are \((x+\sqrt6)(x\sqrt6) \)

magepker728
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but it is not (x3) (x+2)

hartnn
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exatly! its not
because (x3)(x+2) = x^2x6

magepker728
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ooh i see

akash809
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(x3) (x2)= x^22x3x+6=x^25x+6...so u got an extra 5x

hartnn
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ask if still any doubts.

magepker728
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so when ever it is not a perfect square, i have to to take the square root of both side?

CliffSedge
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You have to take the square root regardless.

hartnn
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whenever ?
when its in the form of
x^2  a^2 = 0

hartnn
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then shift a^2 to other side and take square root.

magepker728
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k thanks

hartnn
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welcome :)

febylailani
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bcs u hv 1 exttra x :)

magepker728
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:D