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dnance
Group Title
Find the range if y = 3x + 12 for x = {0.4, 0.6, 1.8, 2.2}.
{1.2, 1.8, 5.4, 6.6}
{13.2, 13.8, 17.4, 18.6}
{12.4, 12.6, 13.8, 14.2}
 one year ago
 one year ago
dnance Group Title
Find the range if y = 3x + 12 for x = {0.4, 0.6, 1.8, 2.2}. {1.2, 1.8, 5.4, 6.6} {13.2, 13.8, 17.4, 18.6} {12.4, 12.6, 13.8, 14.2}
 one year ago
 one year ago

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Loujoelou Group TitleBest ResponseYou've already chosen the best response.1
K so for this problem, all you have to do is pluck in those xvalues and solve. We'll do them one by one :) So when we put in x=0.4 we get, y=3(0.4)+12 (Now we do order of operations and multiply 3*0.4 first) y=1.2+12 and now we add this together and get y=13.2 Now we do the same thing with the other 3 and get: y=3(0.6)+12 y=1.8+12 y=13.8 Now 2 more left: y=3(1.8)+12 y=5.4+12 y=17.4 And the last one: y=3(2.2)+12 y=6.6+12 y=18.6 So by doing this we now know that all our yvalues are 13.2,13.8,17.4,18.6 and that's the second answer :)
 one year ago

dnance Group TitleBest ResponseYou've already chosen the best response.0
ur teachin me stuff,u ready for round 3?
 one year ago

Loujoelou Group TitleBest ResponseYou've already chosen the best response.1
Sure and hey you can just stay here if you want :) I just like helping people learn more about getting medals so it'll be easier for the both of us as well :)
 one year ago

dnance Group TitleBest ResponseYou've already chosen the best response.0
idk what this is trying to get me to do?? John began his job making $25 the first day. After that he was paid $6.75 per hour. Write the linear equation for this problem in y=mx+b form.
 one year ago

Loujoelou Group TitleBest ResponseYou've already chosen the best response.1
Oh okay, so it wants us to put the information you wrote above in an equation that looks like that. So every hour we will get $6.75 so that number will always be constant. Since we don't know how many hours John works, that'll be a variable, x. So so far we have y=$6.75x. Now it also said he got an automatic $25 on the first day so the equation is y=$6.75x+25 :) Did you get it? :)
 one year ago

dnance Group TitleBest ResponseYou've already chosen the best response.0
oh x is how many hours and thats multiplied by how much we get n a hour??
 one year ago

Loujoelou Group TitleBest ResponseYou've already chosen the best response.1
Well we can't solve the equation, we can only make one. To solve it, the problem would have had to say how many hours John actually worked.
 one year ago

dnance Group TitleBest ResponseYou've already chosen the best response.0
now its aking me to do stuff with the same prob but with a t graph ;( idk this stuff
 one year ago

dnance Group TitleBest ResponseYou've already chosen the best response.0
John began his job making $25 the first day. After that he was paid $6.75 per hour.Make a Ttable for the equation for this, using the xvalues: 0, 20, 40. Type in the ordered pairs you get as your answer, in this form: (0, number), (20, number), (40, number).
 one year ago

Loujoelou Group TitleBest ResponseYou've already chosen the best response.1
He gets 6.75 an hours, and we don't know how many hours he worked so that's why we do y=6.75x+25. the X in the equation above is the amount of hours John worked. But we can't put a number for x because the problem doesn't tell us how many hours John worked.
 one year ago

dnance Group TitleBest ResponseYou've already chosen the best response.0
i get that but not this
 one year ago

Loujoelou Group TitleBest ResponseYou've already chosen the best response.1
Oh I get it. You have to make a table. Now though you have to put 0,20, & 40 as the xvalues and solve for your answer.
 one year ago

Loujoelou Group TitleBest ResponseYou've already chosen the best response.1
So our equation we have is y=$6.75x+25. We will pluck in 0,20 & 40 one by one to see what we get. y=$6.75(0)+25 y=0+25 y=$25. y=$6.75(20)+25 y=135+25 y=$160 y=$6.75(40)+25 y=270+25 y=$295
 one year ago

Loujoelou Group TitleBest ResponseYou've already chosen the best response.1
dw:1347661718902:dw I'm pretty sure that's what it's asking for.
 one year ago
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