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lvasquev462

Find the distance between the points (-1, 3) and (5, 0).

  • one year ago
  • one year ago

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  1. _chris
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    \[d = \sqrt{(-1-5)^2 + (3-0)^2}\]

    • one year ago
  2. lvasquev462
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    wi|dw:1347663020094:dw|

    • one year ago
  3. _chris
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    \[\sqrt{45}?\]

    • one year ago
  4. Loujoelou
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    \[\sqrt{(y2-y1)^2+(x2-x1)}\] This is the formula we use to find the distance between points. So if we pluck (-1,3) & (5,0) in this formula we have \[\sqrt{(-1-5)^2+(3-0)^2}\] Then we do what are in bose parenthesis and get- \[\sqrt{(-6)^2+(3)^2}\] Once we put the exponents & add it together we now have- \[\sqrt{45}\]

    • one year ago
  5. lvasquev462
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    There's not a choice in that

    • one year ago
  6. _chris
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    if you round it you get 7 if that helps

    • one year ago
  7. lvasquev462
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    |dw:1347663433928:dw| Those are the choices

    • one year ago
  8. _chris
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    \[3\sqrt{5}\]

    • one year ago
  9. Loujoelou
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    |dw:1347663557537:dw| If we have to simplify \[\sqrt{45}\] we list all the factors of 45. 45=5*3*3. When there's two of a number we can cancel that out and put it on the other side of the square root. That means we then get \[3\sqrt{5}\]

    • one year ago
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