## lvasquev462 Group Title Find the distance between the points (-1, 3) and (5, 0). one year ago one year ago

1. _chris Group Title

$d = \sqrt{(-1-5)^2 + (3-0)^2}$

2. lvasquev462 Group Title

wi|dw:1347663020094:dw|

3. _chris Group Title

$\sqrt{45}?$

4. Loujoelou Group Title

$\sqrt{(y2-y1)^2+(x2-x1)}$ This is the formula we use to find the distance between points. So if we pluck (-1,3) & (5,0) in this formula we have $\sqrt{(-1-5)^2+(3-0)^2}$ Then we do what are in bose parenthesis and get- $\sqrt{(-6)^2+(3)^2}$ Once we put the exponents & add it together we now have- $\sqrt{45}$

5. lvasquev462 Group Title

There's not a choice in that

6. _chris Group Title

if you round it you get 7 if that helps

7. lvasquev462 Group Title

|dw:1347663433928:dw| Those are the choices

8. _chris Group Title

$3\sqrt{5}$

9. Loujoelou Group Title

|dw:1347663557537:dw| If we have to simplify $\sqrt{45}$ we list all the factors of 45. 45=5*3*3. When there's two of a number we can cancel that out and put it on the other side of the square root. That means we then get $3\sqrt{5}$