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lvasquev462
Group Title
Find the distance between the points (1, 3) and (5, 0).
 2 years ago
 2 years ago
lvasquev462 Group Title
Find the distance between the points (1, 3) and (5, 0).
 2 years ago
 2 years ago

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_chris Group TitleBest ResponseYou've already chosen the best response.1
\[d = \sqrt{(15)^2 + (30)^2}\]
 2 years ago

lvasquev462 Group TitleBest ResponseYou've already chosen the best response.0
widw:1347663020094:dw
 2 years ago

_chris Group TitleBest ResponseYou've already chosen the best response.1
\[\sqrt{45}?\]
 2 years ago

Loujoelou Group TitleBest ResponseYou've already chosen the best response.0
\[\sqrt{(y2y1)^2+(x2x1)}\] This is the formula we use to find the distance between points. So if we pluck (1,3) & (5,0) in this formula we have \[\sqrt{(15)^2+(30)^2}\] Then we do what are in bose parenthesis and get \[\sqrt{(6)^2+(3)^2}\] Once we put the exponents & add it together we now have \[\sqrt{45}\]
 2 years ago

lvasquev462 Group TitleBest ResponseYou've already chosen the best response.0
There's not a choice in that
 2 years ago

_chris Group TitleBest ResponseYou've already chosen the best response.1
if you round it you get 7 if that helps
 2 years ago

lvasquev462 Group TitleBest ResponseYou've already chosen the best response.0
dw:1347663433928:dw Those are the choices
 2 years ago

_chris Group TitleBest ResponseYou've already chosen the best response.1
\[3\sqrt{5}\]
 2 years ago

Loujoelou Group TitleBest ResponseYou've already chosen the best response.0
dw:1347663557537:dw If we have to simplify \[\sqrt{45}\] we list all the factors of 45. 45=5*3*3. When there's two of a number we can cancel that out and put it on the other side of the square root. That means we then get \[3\sqrt{5}\]
 2 years ago
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