anonymous
  • anonymous
A boy is practicing tennis by hitting a ball at a wall. He hits the ball at 0.75 m above the ground. The initial speed of the ball is 20.0 m/s at an angle of 32 degrees above the horizontal. How long does it take for the ball to hit the wall if it is 6.7 m away?
Physics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
You can use these two equation: \[y=y_0 +v_0\sin{\alpha}-\frac12 g t^2\] and \[x=v_0 \cos{\alpha}*t\] That's all you need
anonymous
  • anonymous
Can I use either equation to get the answer or do I have to use both somehow?
anonymous
  • anonymous
You have to use both, you might like to find t from second equation first, then substitute to first equation.

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
Ok, I got an answer for t, but I don't understand why I need to plug in that figure to the first equation since I've already found time.
anonymous
  • anonymous
Good, of course you don't need to. This problem's just overresource. Sorry for my previous answer, i'm not concentrating back then :)
anonymous
  • anonymous
Lol.. that's ok. :) Thanks for your help!
anonymous
  • anonymous
Theheh, welcome.

Looking for something else?

Not the answer you are looking for? Search for more explanations.