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consider the rectangle below. It's area is 5a^2+21ab+4b^2 and it's length is 2a+8b. find it's width w, in terms of a and b, by dividing it's area by it's length.
 one year ago
 one year ago
consider the rectangle below. It's area is 5a^2+21ab+4b^2 and it's length is 2a+8b. find it's width w, in terms of a and b, by dividing it's area by it's length.
 one year ago
 one year ago

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KE8717504Best ResponseYou've already chosen the best response.1
dw:1347684283899:dw
 one year ago

jim_thompson5910Best ResponseYou've already chosen the best response.1
what do you have so far
 one year ago

KE8717504Best ResponseYou've already chosen the best response.1
I'm just not sure how to work this.
 one year ago

KE8717504Best ResponseYou've already chosen the best response.1
or how to go about starting it?
 one year ago

jim_thompson5910Best ResponseYou've already chosen the best response.1
Use the idea that Area = Length * Width or A = LW Solve for W W = A/L
 one year ago

jim_thompson5910Best ResponseYou've already chosen the best response.1
Then make the proper substitutions. Then divide and simplify.
 one year ago

KE8717504Best ResponseYou've already chosen the best response.1
@jim_thompson5910 this is what i get when i do that. 2ab^2+5a^2+21ab+8b
 one year ago

KE8717504Best ResponseYou've already chosen the best response.1
That is diving the Area by the length
 one year ago

jim_thompson5910Best ResponseYou've already chosen the best response.1
simplify (5a^2+21ab+4b^2)/(2a+8b)
 one year ago

KE8717504Best ResponseYou've already chosen the best response.1
would that make my width?
 one year ago

jim_thompson5910Best ResponseYou've already chosen the best response.1
Can you factor 5a^2+21ab+4b^2 at all?
 one year ago

KE8717504Best ResponseYou've already chosen the best response.1
yes into (a+4b)(5a+1b) right?
 one year ago

KE8717504Best ResponseYou've already chosen the best response.1
but u still get the same answer right 5a+b/2 right?
 one year ago

jim_thompson5910Best ResponseYou've already chosen the best response.1
Did you mean \[\Large \frac{5a+b}{2}\] ?
 one year ago

KE8717504Best ResponseYou've already chosen the best response.1
@jim_thompson5910 yea
 one year ago

jim_thompson5910Best ResponseYou've already chosen the best response.1
then yes, you are correct
 one year ago

KE8717504Best ResponseYou've already chosen the best response.1
I should get a learners metal on that one :0
 one year ago
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