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can you solve it The value of 1 -(2 -(3 -(.....100.....) is..........

Mathematics
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100's the last term right ?
hi shubham
is hi ka matlab main yes samjhun? :P

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Other answers:

okay
Wouldn't you just work your way out from the inside. 3-100=-97 2-(-97)=99 1-99=-98
What??
@PhoenixFire you are wrong! nice try
How is it wrong?
Oh.. wait
Associative rule. it's the same as 1-2-3-100... work left to right. 1-2=-1 -1-3=-4 -4-100=-104
for u r support I will give you options : A) - 40 B) - 50 c) 50 d) -100 e ) 100 f) 99
It will be like: 1-2+3-4+5-6+7...-100
Sum odd number from 1 to 100 - sum of even number from 1 to 100
Still m not satisfied !! more proofs needed
What do you mean by (......100.......)
100
yeah why there is (.....100...) ?
so it's 1-(2-(3-(100))).... why did you add ........
hmmmm..................
you could write it like @PhoenixFire , what is the significance of those dots?
for your knowledge its INEQUALITY QUESTIOn
:P
Sum of odd number from 1 to 100 -sum of even number from 1 to 100 2500-2550 -50
A simple example : 1/2·3/4·5/6· ... ·99/100 < 1/10. solution : A(n) < 1/√3n,
its just 1-2+3-4+5-6+......100 isn't it ?
then @sauravshakya is right
@sauravshakya you were correct but still add a thing and a medal for u is waiting! :p
?
!!
how can it be Sum of odd number from 1 to 100? there is -3 not 3
1 -(2 -(3 -(.....100.....) =1-2+(3-(...100...) =1-2+3-(4-(5...100...)
lets start from inside,, ............-(95 - (96 - (97 - ( 98 - ( 99 -100) ) ) ) ) ) ............-(95 - (96 -(97 - (98 - 99 + 100 ) .... ..........-(95 - (96 - (97 - 98 + 99 - 100 ).. .........-(95 - 96 + 97 - 98 + 99 - 100) sign alternates everytime for each no..i.e. 2 consecutive nos. have opposite signs.. in the end, we shall have 1- 2 +3 - 4 ......... -100 (1+3+5......99) - (2 +4 +6 ...100) 25(100 - 102) =-50 was that corretc ?
Open the bracket one by one and see
YEp very correct @shubhamsrg

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