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anonymous
 3 years ago
Okay, so I'm new to chemistry and absolutely confused. Can anyone please explain to me how to solve the following?? Mg > ____ + 2e ....Help would be very much appreciated!!
anonymous
 3 years ago
Okay, so I'm new to chemistry and absolutely confused. Can anyone please explain to me how to solve the following?? Mg > ____ + 2e ....Help would be very much appreciated!!

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[mg \rightarrow mg ^{2+} + 2 e\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0thats awesome thank you sooooo much. I still have three more to figure out, could you explain how to do it?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i'm sowry.. i don't know how to explain it...

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0thats okay, thanks for the help you did give me though. :)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0we must make it neutral :) do u understand?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0well, that i get, im just not sure how to do so. For example: Ba > Ba^(2+) + _______ ??? How would i get rid of the two? is that what yhou mean im supposed to do? sorry, chemistry is very confusing to me...

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ah.. how to explain it. if 2e = debt (2) so, we must pay it by +2. just like that. but, we must write it on the righttop the element (Mg)

UnkleRhaukus
 3 years ago
Best ResponseYou've already chosen the best response.0well, magnesium has 12 protons  by definition, to be a neutral atom the positive charges of the protons is canceled out by negatively charged electrons , ()elections and (+)protons have a charge that is equal in magnitude and opposite in sign, \[ _{12}\text{Mg}^0 \longrightarrow \_\_ + 2e^ \] \[ _{12}\text{Mg}^0 2e^ = \_\_ \] taking away electrons from magnesium will effect the overall charge \(0(2)=2\) the nucleus of the atom will remain the same

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0yup, u must pay it by ...... electron(s). to make it neutral :)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0So, would it be Ba^(2) ?? Sorry for asking so many questions. I just want to be sure.

UnkleRhaukus
 3 years ago
Best ResponseYou've already chosen the best response.0\[_{12}\text{Mg}^0 2\times_0e^{1} =~ _{12}\text{Mg}^{2+}\]
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