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Okay, so I'm new to chemistry and absolutely confused. Can anyone please explain to me how to solve the following?? Mg > ____ + 2e ....Help would be very much appreciated!!
 one year ago
 one year ago
Okay, so I'm new to chemistry and absolutely confused. Can anyone please explain to me how to solve the following?? Mg > ____ + 2e ....Help would be very much appreciated!!
 one year ago
 one year ago

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cozuwhoiluv2Best ResponseYou've already chosen the best response.1
\[mg \rightarrow mg ^{2+} + 2 e\]
 one year ago

GamerChick333Best ResponseYou've already chosen the best response.0
thats awesome thank you sooooo much. I still have three more to figure out, could you explain how to do it?
 one year ago

cozuwhoiluv2Best ResponseYou've already chosen the best response.1
i'm sowry.. i don't know how to explain it...
 one year ago

GamerChick333Best ResponseYou've already chosen the best response.0
thats okay, thanks for the help you did give me though. :)
 one year ago

febylailaniBest ResponseYou've already chosen the best response.0
we must make it neutral :) do u understand?
 one year ago

GamerChick333Best ResponseYou've already chosen the best response.0
well, that i get, im just not sure how to do so. For example: Ba > Ba^(2+) + _______ ??? How would i get rid of the two? is that what yhou mean im supposed to do? sorry, chemistry is very confusing to me...
 one year ago

febylailaniBest ResponseYou've already chosen the best response.0
ah.. how to explain it. if 2e = debt (2) so, we must pay it by +2. just like that. but, we must write it on the righttop the element (Mg)
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.0
well, magnesium has 12 protons  by definition, to be a neutral atom the positive charges of the protons is canceled out by negatively charged electrons , ()elections and (+)protons have a charge that is equal in magnitude and opposite in sign, \[ _{12}\text{Mg}^0 \longrightarrow \_\_ + 2e^ \] \[ _{12}\text{Mg}^0 2e^ = \_\_ \] taking away electrons from magnesium will effect the overall charge \(0(2)=2\) the nucleus of the atom will remain the same
 one year ago

febylailaniBest ResponseYou've already chosen the best response.0
yup, u must pay it by ...... electron(s). to make it neutral :)
 one year ago

GamerChick333Best ResponseYou've already chosen the best response.0
So, would it be Ba^(2) ?? Sorry for asking so many questions. I just want to be sure.
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.0
\[_{12}\text{Mg}^0 2\times_0e^{1} =~ _{12}\text{Mg}^{2+}\]
 one year ago

GamerChick333Best ResponseYou've already chosen the best response.0
Thanks everybody =D
 one year ago
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