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GamerChick333
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Okay, so I'm new to chemistry and absolutely confused. Can anyone please explain to me how to solve the following?? Mg > ____ + 2e ....Help would be very much appreciated!!
 2 years ago
 2 years ago
GamerChick333 Group Title
Okay, so I'm new to chemistry and absolutely confused. Can anyone please explain to me how to solve the following?? Mg > ____ + 2e ....Help would be very much appreciated!!
 2 years ago
 2 years ago

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cozuwhoiluv2 Group TitleBest ResponseYou've already chosen the best response.1
\[mg \rightarrow mg ^{2+} + 2 e\]
 2 years ago

GamerChick333 Group TitleBest ResponseYou've already chosen the best response.0
thats awesome thank you sooooo much. I still have three more to figure out, could you explain how to do it?
 2 years ago

cozuwhoiluv2 Group TitleBest ResponseYou've already chosen the best response.1
i'm sowry.. i don't know how to explain it...
 2 years ago

GamerChick333 Group TitleBest ResponseYou've already chosen the best response.0
thats okay, thanks for the help you did give me though. :)
 2 years ago

febylailani Group TitleBest ResponseYou've already chosen the best response.0
we must make it neutral :) do u understand?
 2 years ago

GamerChick333 Group TitleBest ResponseYou've already chosen the best response.0
well, that i get, im just not sure how to do so. For example: Ba > Ba^(2+) + _______ ??? How would i get rid of the two? is that what yhou mean im supposed to do? sorry, chemistry is very confusing to me...
 2 years ago

febylailani Group TitleBest ResponseYou've already chosen the best response.0
ah.. how to explain it. if 2e = debt (2) so, we must pay it by +2. just like that. but, we must write it on the righttop the element (Mg)
 2 years ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.0
well, magnesium has 12 protons  by definition, to be a neutral atom the positive charges of the protons is canceled out by negatively charged electrons , ()elections and (+)protons have a charge that is equal in magnitude and opposite in sign, \[ _{12}\text{Mg}^0 \longrightarrow \_\_ + 2e^ \] \[ _{12}\text{Mg}^0 2e^ = \_\_ \] taking away electrons from magnesium will effect the overall charge \(0(2)=2\) the nucleus of the atom will remain the same
 2 years ago

febylailani Group TitleBest ResponseYou've already chosen the best response.0
yup, u must pay it by ...... electron(s). to make it neutral :)
 2 years ago

GamerChick333 Group TitleBest ResponseYou've already chosen the best response.0
So, would it be Ba^(2) ?? Sorry for asking so many questions. I just want to be sure.
 2 years ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.0
\[_{12}\text{Mg}^0 2\times_0e^{1} =~ _{12}\text{Mg}^{2+}\]
 2 years ago

GamerChick333 Group TitleBest ResponseYou've already chosen the best response.0
Thanks everybody =D
 2 years ago
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