## GamerChick333 Group Title Okay, so I'm new to chemistry and absolutely confused. Can anyone please explain to me how to solve the following?? Mg -> ____ + 2e- ....Help would be very much appreciated!! one year ago one year ago

1. cozuwhoiluv2 Group Title

$mg \rightarrow mg ^{2+} + 2 e$

2. GamerChick333 Group Title

thats awesome thank you sooooo much. I still have three more to figure out, could you explain how to do it?

3. cozuwhoiluv2 Group Title

i'm sowry.. i don't know how to explain it...

4. GamerChick333 Group Title

thats okay, thanks for the help you did give me though. :)

5. febylailani Group Title

we must make it neutral :) do u understand?

6. GamerChick333 Group Title

well, that i get, im just not sure how to do so. For example: Ba -> Ba^(2+) + _______ ??? How would i get rid of the two? is that what yhou mean im supposed to do? sorry, chemistry is very confusing to me...

7. febylailani Group Title

ah.. how to explain it. if 2e = debt (-2) so, we must pay it by +2. just like that. but, we must write it on the right-top the element (Mg)

8. UnkleRhaukus Group Title

well, magnesium has 12 protons - by definition, to be a neutral atom the positive charges of the protons is canceled out by negatively charged electrons , (-)elections and (+)protons have a charge that is equal in magnitude and opposite in sign, $_{12}\text{Mg}^0 \longrightarrow \_\_ + 2e^-$ $_{12}\text{Mg}^0 -2e^- = \_\_$ taking away electrons from magnesium will effect the overall charge $$0-(-2)=2$$ the nucleus of the atom will remain the same

9. febylailani Group Title

yup, u must pay it by ...... electron(s). to make it neutral :)

10. GamerChick333 Group Title

So, would it be Ba^(2-) ?? Sorry for asking so many questions. I just want to be sure.

11. UnkleRhaukus Group Title

$_{12}\text{Mg}^0 -2\times_0e^{-1} =~ _{12}\text{Mg}^{2+}$

12. GamerChick333 Group Title

Thanks everybody =D

13. febylailani Group Title

uwc :)