anonymous
  • anonymous
Okay, so I'm new to chemistry and absolutely confused. Can anyone please explain to me how to solve the following?? Mg -> ____ + 2e- ....Help would be very much appreciated!!
Chemistry
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
\[mg \rightarrow mg ^{2+} + 2 e\]
anonymous
  • anonymous
thats awesome thank you sooooo much. I still have three more to figure out, could you explain how to do it?
anonymous
  • anonymous
i'm sowry.. i don't know how to explain it...

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anonymous
  • anonymous
thats okay, thanks for the help you did give me though. :)
anonymous
  • anonymous
we must make it neutral :) do u understand?
anonymous
  • anonymous
well, that i get, im just not sure how to do so. For example: Ba -> Ba^(2+) + _______ ??? How would i get rid of the two? is that what yhou mean im supposed to do? sorry, chemistry is very confusing to me...
anonymous
  • anonymous
ah.. how to explain it. if 2e = debt (-2) so, we must pay it by +2. just like that. but, we must write it on the right-top the element (Mg)
UnkleRhaukus
  • UnkleRhaukus
well, magnesium has 12 protons - by definition, to be a neutral atom the positive charges of the protons is canceled out by negatively charged electrons , (-)elections and (+)protons have a charge that is equal in magnitude and opposite in sign, \[ _{12}\text{Mg}^0 \longrightarrow \_\_ + 2e^- \] \[ _{12}\text{Mg}^0 -2e^- = \_\_ \] taking away electrons from magnesium will effect the overall charge \(0-(-2)=2\) the nucleus of the atom will remain the same
anonymous
  • anonymous
yup, u must pay it by ...... electron(s). to make it neutral :)
anonymous
  • anonymous
So, would it be Ba^(2-) ?? Sorry for asking so many questions. I just want to be sure.
UnkleRhaukus
  • UnkleRhaukus
\[_{12}\text{Mg}^0 -2\times_0e^{-1} =~ _{12}\text{Mg}^{2+}\]
anonymous
  • anonymous
Thanks everybody =D
anonymous
  • anonymous
uwc :)

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