Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing

This Question is Closed

hartnnBest ResponseYou've already chosen the best response.1
\[f(x)=\sqrt{x^2+x+2}\sqrt{x^2+x+1}\]
 one year ago

sauravshakyaBest ResponseYou've already chosen the best response.3
I think dw:1347709678855:dw
 one year ago

estudierBest ResponseYou've already chosen the best response.0
always positive, diff for max
 one year ago

sauravshakyaBest ResponseYou've already chosen the best response.3
x^2+x+2=(x+1/2)^2 +7/4 x^2+x+1=(x+1/2)^2+3/4 Now, f(x) is maximum when (x+1/2)^=0 because the f(x) value decresases as (x+1/2)^2 is greater than 0 since dw:1347710167952:dw Now, when (x+1/2)^2 >approaches infinity f(x) will be minimum but will never be zero.....but will be very close to zero
 one year ago

sauravshakyaBest ResponseYou've already chosen the best response.3
Sorry not good at expalining things
 one year ago

sauravshakyaBest ResponseYou've already chosen the best response.3
But I think thats it
 one year ago

mukushlaBest ResponseYou've already chosen the best response.1
\[f(x)=\frac{1}{\sqrt{x^2+x+2}+\sqrt{x^2+x+1}}\]
 one year ago

sauravshakyaBest ResponseYou've already chosen the best response.3
Is that another question?
 one year ago

mukushlaBest ResponseYou've already chosen the best response.1
\[f(x)=\sqrt{x^2+x+2}\sqrt{x^2+x+1}\times\frac{\sqrt{x^2+x+2}+\sqrt{x^2+x+1}}{\sqrt{x^2+x+2}+\sqrt{x^2+x+1}}\]
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
just rationalizing the denom, isn't it ?
 one year ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.