## KE8717504 3 years ago see attatched picture.

1. AravindG

waitin..

2. mathslover

3. KE8717504

|dw:1347725910297:dw|

4. KE8717504

I have the find the polynomial where the x is?

5. KE8717504

where the ? mark is i mean

6. AravindG

first try to factorise the given plynomials

7. AravindG

do cancellation wherever possible

8. KE8717504

ok give me a sec to do that.

9. KE8717504

so when i factored and cancelled out i am left with (x-4)(3x+7)

10. KE8717504

so what do i do now?

11. AravindG

divide both sides with (x-4)(3x+7) you will get the answr

12. KE8717504

@AravindG when u do that does that not cancel them out?

13. AravindG

ya u will get ?= answer

14. KE8717504

Can u set up what i'm suppose to do im confused?

15. KE8717504

sorry lol

16. KE8717504

I can solve it i just need help setting it up

17. KE8717504

r u there?

18. KE8717504

@ArkGoLucky

19. KE8717504

20. KE8717504

@tyteen4a03

21. KE8717504

@Algebraic! can u help me please????

22. Algebraic!

did you factor the x^2-9 ?

23. KE8717504

yea

24. Algebraic!

you factored everything, you cancelled everything, you're left with (x-4)(3x+7) I think you're done... but I don't really know what instructions you were given, so...

25. Algebraic!

26. KE8717504

i was just told to find the polynomial where the ? is

27. Algebraic!

makes no sense without more info. what are you trying to achieve by putting a polynomial there? so that the whole thing equals 1 or something?

28. KE8717504

yea its equal to 1..

29. Algebraic!

...

30. Algebraic!

ok... what's the denominator on the right hand term... it's cut off in the picture.. 3x^2 +16x -.....?

31. KE8717504

+21

32. Algebraic!

so yeah, your new denominator is (x-4)(3x+7)... so that's what needs to go where the "?" is in order to make the whole thing 'cancel' (make the whole thing equal 1)

33. KE8717504

so (x-4)(3x+7)

34. KE8717504

35. Algebraic!

k

36. Algebraic!

so what IS the question?

37. KE8717504

To find the polynomial where the ? mark is

38. Algebraic!

very funny

39. KE8717504