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MikaelBest ResponseYou've already chosen the best response.0
Look ziz iz a seempl applicashion of limit lohz:dw:1347737182410:dw
 one year ago

MikaelBest ResponseYou've already chosen the best response.0
Now , since \[\lim_{x \rightarrow 0} \cos(x) = 1\]
 one year ago

MikaelBest ResponseYou've already chosen the best response.0
And, on the other hand \[\lim_{x \rightarrow 0} x^4 = 0\]
 one year ago

MikaelBest ResponseYou've already chosen the best response.0
You have the product of those two being (surprise , surprise !) 0
 one year ago

MikaelBest ResponseYou've already chosen the best response.0
Ahh sorry it is 2/x so here is the correct solution:
 one year ago

MikaelBest ResponseYou've already chosen the best response.0
Theorem we all can use states that Product of a Bounded function by another function that tends to zero  also tends to ZERO in the same limit
 one year ago

RaphaelFilgueirasBest ResponseYou've already chosen the best response.2
use squeeze theorem
 one year ago

MikaelBest ResponseYou've already chosen the best response.0
Buut\[\cos(\frac{2}{x}) \leq 1, alwayz\]
 one year ago

MikaelBest ResponseYou've already chosen the best response.0
So we do have true the required assumptions: One of the factors (i.e. cos 2/x) is a bounded function while the other factor : x^4 tends to 0 when x>0
 one year ago

RaphaelFilgueirasBest ResponseYou've already chosen the best response.2
dw:1347737519682:dw
 one year ago
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