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add -8 to both sides

well i got to this part x^3-19=0

no
\[ \large (x-3)^3=-8 \]

k then

now take cubic roots of each side

x-3=2i?

yes

no
\[ \large \sqrt[3]{(x-3)^3}=\sqrt[3]{-8}=-2 \]

then u have
\[ \large x-3=-2 \]

ook so now why did you subtract 8 from both side instead of doing the parenthesis

so how do know when to do your method

how would i know when do apply your method

did they teach the order of operations?

nop

come on... for real??

oo my bad didnt read read the question right

well. take a look at this
\[ \large (7-3)^8+8= \]

tell me step by step how would u compute this

great

to solve an equation u do that but in reverse order:
1st undo +8
2nd undo ^3
3rd undo -3
got it?

hmm

did they (your teachers) taught you this?

i dont remember something like this lol