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aroub Group TitleBest ResponseYou've already chosen the best response.0
lol, more of a fail . So, this is the question: \[\sqrt[4]{6} \times \sqrt[4]{36} \times \sqrt[4]{192}\]
 one year ago

aroub Group TitleBest ResponseYou've already chosen the best response.0
I know it looks easy, I just keep on getting different answer :/
 one year ago

aroub Group TitleBest ResponseYou've already chosen the best response.0
I got \[2\sqrt[4]{2592}\] Yeah . It looks wrong .
 one year ago

Hero Group TitleBest ResponseYou've already chosen the best response.0
If it has the same root....
 one year ago

Hero Group TitleBest ResponseYou've already chosen the best response.0
rewrite it like this: \[\large \sqrt[4]{6 \times 36 \times 192}\]
 one year ago

aroub Group TitleBest ResponseYou've already chosen the best response.0
Yes, this is what I did..
 one year ago

phi Group TitleBest ResponseYou've already chosen the best response.2
I would never multiply these numbers together. on the contrary, you want to factor them all are under the root sign. so you have \[ 6 \cdot 6^2 \cdot 6\cdot 2^5 \] or \[ 6^4 \cdot 2^4 \cdot 2\] pull out the powers of 4
 one year ago

RaphaelFilgueiras Group TitleBest ResponseYou've already chosen the best response.0
dw:1347737858173:dw
 one year ago

Hero Group TitleBest ResponseYou've already chosen the best response.0
I didn't multiply them together. I just simplified them under one root @phi. I agree that what you did would be the next step AFTER putting them under one root
 one year ago

helder_edwin Group TitleBest ResponseYou've already chosen the best response.0
sorry. i got \[ \large 12\sqrt[4]{2} \]
 one year ago

phi Group TitleBest ResponseYou've already chosen the best response.2
@Hero that was to @aroub not you. I know you know how to do it!
 one year ago

aroub Group TitleBest ResponseYou've already chosen the best response.0
I didn't multiply them together at first. This is was what I did (it's stupid though compared to what you did): \[\sqrt[4]{3\times2 \times 6^2\times2^6\times3} = \sqrt[4]{3^2\times2^4\times6^2\times2^3}\] Don't ask me how or why :P And then after realizing I cant factor them more I multiplied them.
 one year ago

aroub Group TitleBest ResponseYou've already chosen the best response.0
Thank you phi and everyone!! =D
 one year ago

phi Group TitleBest ResponseYou've already chosen the best response.2
doing that is fine. The only mistake is not factor the 6^2 into 2^2 * 3^2 after combining bases, you would have gotten 3^4 2^9 or 3^4 * 2^4 * 2^4 * 2 take the 4th root, you would get 3*2*2 * 2^(1/4) or 12* 2^(1/4)
 one year ago

aroub Group TitleBest ResponseYou've already chosen the best response.0
If i still want the square root that would be equal to \[12\sqrt[4]{2}?\]
 one year ago

phi Group TitleBest ResponseYou've already chosen the best response.2
yes, but it is the 4th root (not the square root)
 one year ago

aroub Group TitleBest ResponseYou've already chosen the best response.0
Oh yeah sorry . I'm used to square roots :P
 one year ago
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