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aroub
 4 years ago
sqrt[4]{6} times sqrt[4]{36} times sqrt[4]{192}
aroub
 4 years ago
sqrt[4]{6} times sqrt[4]{36} times sqrt[4]{192}

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aroub
 4 years ago
Best ResponseYou've already chosen the best response.0lol, more of a fail . So, this is the question: \[\sqrt[4]{6} \times \sqrt[4]{36} \times \sqrt[4]{192}\]

aroub
 4 years ago
Best ResponseYou've already chosen the best response.0I know it looks easy, I just keep on getting different answer :/

aroub
 4 years ago
Best ResponseYou've already chosen the best response.0I got \[2\sqrt[4]{2592}\] Yeah . It looks wrong .

Hero
 4 years ago
Best ResponseYou've already chosen the best response.0If it has the same root....

Hero
 4 years ago
Best ResponseYou've already chosen the best response.0rewrite it like this: \[\large \sqrt[4]{6 \times 36 \times 192}\]

aroub
 4 years ago
Best ResponseYou've already chosen the best response.0Yes, this is what I did..

phi
 4 years ago
Best ResponseYou've already chosen the best response.2I would never multiply these numbers together. on the contrary, you want to factor them all are under the root sign. so you have \[ 6 \cdot 6^2 \cdot 6\cdot 2^5 \] or \[ 6^4 \cdot 2^4 \cdot 2\] pull out the powers of 4

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1347737858173:dw

Hero
 4 years ago
Best ResponseYou've already chosen the best response.0I didn't multiply them together. I just simplified them under one root @phi. I agree that what you did would be the next step AFTER putting them under one root

helder_edwin
 4 years ago
Best ResponseYou've already chosen the best response.0sorry. i got \[ \large 12\sqrt[4]{2} \]

phi
 4 years ago
Best ResponseYou've already chosen the best response.2@Hero that was to @aroub not you. I know you know how to do it!

aroub
 4 years ago
Best ResponseYou've already chosen the best response.0I didn't multiply them together at first. This is was what I did (it's stupid though compared to what you did): \[\sqrt[4]{3\times2 \times 6^2\times2^6\times3} = \sqrt[4]{3^2\times2^4\times6^2\times2^3}\] Don't ask me how or why :P And then after realizing I cant factor them more I multiplied them.

aroub
 4 years ago
Best ResponseYou've already chosen the best response.0Thank you phi and everyone!! =D

phi
 4 years ago
Best ResponseYou've already chosen the best response.2doing that is fine. The only mistake is not factor the 6^2 into 2^2 * 3^2 after combining bases, you would have gotten 3^4 2^9 or 3^4 * 2^4 * 2^4 * 2 take the 4th root, you would get 3*2*2 * 2^(1/4) or 12* 2^(1/4)

aroub
 4 years ago
Best ResponseYou've already chosen the best response.0If i still want the square root that would be equal to \[12\sqrt[4]{2}?\]

phi
 4 years ago
Best ResponseYou've already chosen the best response.2yes, but it is the 4th root (not the square root)

aroub
 4 years ago
Best ResponseYou've already chosen the best response.0Oh yeah sorry . I'm used to square roots :P
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