andriod09
  • andriod09
Solve
Mathematics
chestercat
  • chestercat
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andriod09
  • andriod09
\[\sqrt{2y-3}+3=y\]
andriod09
  • andriod09
@cshalvey
andriod09
  • andriod09
@.UserNotFound. @jazy @cshalvey

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andriod09
  • andriod09
@KingGeorge
KingGeorge
  • KingGeorge
In the future, please refrain from tagging a bunch of users. Anyways, first move the 3 over.\[\sqrt{2y-3}+3=y\]\[\sqrt{2y-3}=y-3\]Now square both sides. Can you tell me what youget?
andriod09
  • andriod09
sorry, they're all the people that i have fanned for helping me.
KingGeorge
  • KingGeorge
No worries, just something to remember for the future. Anyway, can you tell me what you get after squaring both sides?
andriod09
  • andriod09
\[\left( \sqrt{2y-3} \right)^{2}=\left( y+3 \right)^{2}\] \[\left( 2y-3 \right)=\left(y ^{2}+9 \right)\]
KingGeorge
  • KingGeorge
The left side looks good. The right is not correct. Remember that you need to FOIL. Can you try again?
andriod09
  • andriod09
whats a "FOIL"?
KingGeorge
  • KingGeorge
It's an acronym for First Outer Inner Last It means you first multiply the first two numbers together, then the outer numbers together, then the inner, and then the last numbers. Once you've done that, you add them all. For example: \[(y+3)(y+2)\] First: \((\color{red}y+3)(\color{red}y+2)\implies y\cdot y=y^2\) Outer: \((\color{red}y+3)(y+\color{red}2)\implies y\cdot 2=2y\) Inner: \((y+\color{red}3)(\color{red}y+2)\implies 3\cdot y=3y\) Last: \((y+\color{red}3)(y+\color{red}2)\implies 3\cdot2=6\) So \((y+3)(y+2)=y^2+2y+3y+6=y^2+5y+6\)
KingGeorge
  • KingGeorge
Now can you try the same thing with \((y+3)^2=(y+3)(y+3)\)?
KingGeorge
  • KingGeorge
Oh, and it should be \((y-3)^2=(y-3)(y-3)\). Oops :(
andriod09
  • andriod09
\[\left( y+3 \right)\left( y+3 \right)\] \[y^{2}+3y+3y+9?\]
KingGeorge
  • KingGeorge
Right, and if you had \((y-3)(y-3)\), it would become something similar. You get \[y^2-3y-3y+9=y^2-6y+9\] This means you have \[2y-3=y^2-6y+9\]Get 0 on one side, and you get \[y^2-8y+12=0\]Now you just need to factor this. Can you manage that yourself?
andriod09
  • andriod09
yes i can. Thank you soo much king. for every thing. ima fan you
KingGeorge
  • KingGeorge
You're welcome. Feel free to post what you get as solutions and I can check them if you want.
andriod09
  • andriod09
kk will do. Thanks

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