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andriod09 Group TitleBest ResponseYou've already chosen the best response.0
\[\sqrt{2y3}+3=y\]
 2 years ago

andriod09 Group TitleBest ResponseYou've already chosen the best response.0
@cshalvey
 2 years ago

andriod09 Group TitleBest ResponseYou've already chosen the best response.0
@.UserNotFound. @jazy @cshalvey
 2 years ago

andriod09 Group TitleBest ResponseYou've already chosen the best response.0
@KingGeorge
 2 years ago

KingGeorge Group TitleBest ResponseYou've already chosen the best response.3
In the future, please refrain from tagging a bunch of users. Anyways, first move the 3 over.\[\sqrt{2y3}+3=y\]\[\sqrt{2y3}=y3\]Now square both sides. Can you tell me what youget?
 2 years ago

andriod09 Group TitleBest ResponseYou've already chosen the best response.0
sorry, they're all the people that i have fanned for helping me.
 2 years ago

KingGeorge Group TitleBest ResponseYou've already chosen the best response.3
No worries, just something to remember for the future. Anyway, can you tell me what you get after squaring both sides?
 2 years ago

andriod09 Group TitleBest ResponseYou've already chosen the best response.0
\[\left( \sqrt{2y3} \right)^{2}=\left( y+3 \right)^{2}\] \[\left( 2y3 \right)=\left(y ^{2}+9 \right)\]
 2 years ago

KingGeorge Group TitleBest ResponseYou've already chosen the best response.3
The left side looks good. The right is not correct. Remember that you need to FOIL. Can you try again?
 2 years ago

andriod09 Group TitleBest ResponseYou've already chosen the best response.0
whats a "FOIL"?
 2 years ago

KingGeorge Group TitleBest ResponseYou've already chosen the best response.3
It's an acronym for First Outer Inner Last It means you first multiply the first two numbers together, then the outer numbers together, then the inner, and then the last numbers. Once you've done that, you add them all. For example: \[(y+3)(y+2)\] First: \((\color{red}y+3)(\color{red}y+2)\implies y\cdot y=y^2\) Outer: \((\color{red}y+3)(y+\color{red}2)\implies y\cdot 2=2y\) Inner: \((y+\color{red}3)(\color{red}y+2)\implies 3\cdot y=3y\) Last: \((y+\color{red}3)(y+\color{red}2)\implies 3\cdot2=6\) So \((y+3)(y+2)=y^2+2y+3y+6=y^2+5y+6\)
 2 years ago

KingGeorge Group TitleBest ResponseYou've already chosen the best response.3
Now can you try the same thing with \((y+3)^2=(y+3)(y+3)\)?
 2 years ago

KingGeorge Group TitleBest ResponseYou've already chosen the best response.3
Oh, and it should be \((y3)^2=(y3)(y3)\). Oops :(
 2 years ago

andriod09 Group TitleBest ResponseYou've already chosen the best response.0
\[\left( y+3 \right)\left( y+3 \right)\] \[y^{2}+3y+3y+9?\]
 2 years ago

KingGeorge Group TitleBest ResponseYou've already chosen the best response.3
Right, and if you had \((y3)(y3)\), it would become something similar. You get \[y^23y3y+9=y^26y+9\] This means you have \[2y3=y^26y+9\]Get 0 on one side, and you get \[y^28y+12=0\]Now you just need to factor this. Can you manage that yourself?
 2 years ago

andriod09 Group TitleBest ResponseYou've already chosen the best response.0
yes i can. Thank you soo much king. for every thing. ima fan you
 2 years ago

KingGeorge Group TitleBest ResponseYou've already chosen the best response.3
You're welcome. Feel free to post what you get as solutions and I can check them if you want.
 2 years ago

andriod09 Group TitleBest ResponseYou've already chosen the best response.0
kk will do. Thanks
 2 years ago
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