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andriod09 Group Title

Solve

  • 2 years ago
  • 2 years ago

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  1. andriod09 Group Title
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    \[\sqrt{2y-3}+3=y\]

    • 2 years ago
  2. andriod09 Group Title
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    @cshalvey

    • 2 years ago
  3. andriod09 Group Title
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    @.UserNotFound. @jazy @cshalvey

    • 2 years ago
  4. andriod09 Group Title
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    @KingGeorge

    • 2 years ago
  5. KingGeorge Group Title
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    In the future, please refrain from tagging a bunch of users. Anyways, first move the 3 over.\[\sqrt{2y-3}+3=y\]\[\sqrt{2y-3}=y-3\]Now square both sides. Can you tell me what youget?

    • 2 years ago
  6. andriod09 Group Title
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    sorry, they're all the people that i have fanned for helping me.

    • 2 years ago
  7. KingGeorge Group Title
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    No worries, just something to remember for the future. Anyway, can you tell me what you get after squaring both sides?

    • 2 years ago
  8. andriod09 Group Title
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    \[\left( \sqrt{2y-3} \right)^{2}=\left( y+3 \right)^{2}\] \[\left( 2y-3 \right)=\left(y ^{2}+9 \right)\]

    • 2 years ago
  9. KingGeorge Group Title
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    The left side looks good. The right is not correct. Remember that you need to FOIL. Can you try again?

    • 2 years ago
  10. andriod09 Group Title
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    whats a "FOIL"?

    • 2 years ago
  11. KingGeorge Group Title
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    It's an acronym for First Outer Inner Last It means you first multiply the first two numbers together, then the outer numbers together, then the inner, and then the last numbers. Once you've done that, you add them all. For example: \[(y+3)(y+2)\] First: \((\color{red}y+3)(\color{red}y+2)\implies y\cdot y=y^2\) Outer: \((\color{red}y+3)(y+\color{red}2)\implies y\cdot 2=2y\) Inner: \((y+\color{red}3)(\color{red}y+2)\implies 3\cdot y=3y\) Last: \((y+\color{red}3)(y+\color{red}2)\implies 3\cdot2=6\) So \((y+3)(y+2)=y^2+2y+3y+6=y^2+5y+6\)

    • 2 years ago
  12. KingGeorge Group Title
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    Now can you try the same thing with \((y+3)^2=(y+3)(y+3)\)?

    • 2 years ago
  13. KingGeorge Group Title
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    Oh, and it should be \((y-3)^2=(y-3)(y-3)\). Oops :(

    • 2 years ago
  14. andriod09 Group Title
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    \[\left( y+3 \right)\left( y+3 \right)\] \[y^{2}+3y+3y+9?\]

    • 2 years ago
  15. KingGeorge Group Title
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    Right, and if you had \((y-3)(y-3)\), it would become something similar. You get \[y^2-3y-3y+9=y^2-6y+9\] This means you have \[2y-3=y^2-6y+9\]Get 0 on one side, and you get \[y^2-8y+12=0\]Now you just need to factor this. Can you manage that yourself?

    • 2 years ago
  16. andriod09 Group Title
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    yes i can. Thank you soo much king. for every thing. ima fan you

    • 2 years ago
  17. KingGeorge Group Title
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    You're welcome. Feel free to post what you get as solutions and I can check them if you want.

    • 2 years ago
  18. andriod09 Group Title
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    kk will do. Thanks

    • 2 years ago
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