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andriod09 Group Title

Solve

  • one year ago
  • one year ago

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  1. andriod09 Group Title
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    \[\sqrt{2y-3}+3=y\]

    • one year ago
  2. andriod09 Group Title
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    @cshalvey

    • one year ago
  3. andriod09 Group Title
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    @.UserNotFound. @jazy @cshalvey

    • one year ago
  4. andriod09 Group Title
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    @KingGeorge

    • one year ago
  5. KingGeorge Group Title
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    In the future, please refrain from tagging a bunch of users. Anyways, first move the 3 over.\[\sqrt{2y-3}+3=y\]\[\sqrt{2y-3}=y-3\]Now square both sides. Can you tell me what youget?

    • one year ago
  6. andriod09 Group Title
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    sorry, they're all the people that i have fanned for helping me.

    • one year ago
  7. KingGeorge Group Title
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    No worries, just something to remember for the future. Anyway, can you tell me what you get after squaring both sides?

    • one year ago
  8. andriod09 Group Title
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    \[\left( \sqrt{2y-3} \right)^{2}=\left( y+3 \right)^{2}\] \[\left( 2y-3 \right)=\left(y ^{2}+9 \right)\]

    • one year ago
  9. KingGeorge Group Title
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    The left side looks good. The right is not correct. Remember that you need to FOIL. Can you try again?

    • one year ago
  10. andriod09 Group Title
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    whats a "FOIL"?

    • one year ago
  11. KingGeorge Group Title
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    It's an acronym for First Outer Inner Last It means you first multiply the first two numbers together, then the outer numbers together, then the inner, and then the last numbers. Once you've done that, you add them all. For example: \[(y+3)(y+2)\] First: \((\color{red}y+3)(\color{red}y+2)\implies y\cdot y=y^2\) Outer: \((\color{red}y+3)(y+\color{red}2)\implies y\cdot 2=2y\) Inner: \((y+\color{red}3)(\color{red}y+2)\implies 3\cdot y=3y\) Last: \((y+\color{red}3)(y+\color{red}2)\implies 3\cdot2=6\) So \((y+3)(y+2)=y^2+2y+3y+6=y^2+5y+6\)

    • one year ago
  12. KingGeorge Group Title
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    Now can you try the same thing with \((y+3)^2=(y+3)(y+3)\)?

    • one year ago
  13. KingGeorge Group Title
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    Oh, and it should be \((y-3)^2=(y-3)(y-3)\). Oops :(

    • one year ago
  14. andriod09 Group Title
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    \[\left( y+3 \right)\left( y+3 \right)\] \[y^{2}+3y+3y+9?\]

    • one year ago
  15. KingGeorge Group Title
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    Right, and if you had \((y-3)(y-3)\), it would become something similar. You get \[y^2-3y-3y+9=y^2-6y+9\] This means you have \[2y-3=y^2-6y+9\]Get 0 on one side, and you get \[y^2-8y+12=0\]Now you just need to factor this. Can you manage that yourself?

    • one year ago
  16. andriod09 Group Title
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    yes i can. Thank you soo much king. for every thing. ima fan you

    • one year ago
  17. KingGeorge Group Title
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    You're welcome. Feel free to post what you get as solutions and I can check them if you want.

    • one year ago
  18. andriod09 Group Title
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    kk will do. Thanks

    • one year ago
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