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\[\sqrt{2y-3}+3=y\]

sorry, they're all the people that i have fanned for helping me.

whats a "FOIL"?

Now can you try the same thing with \((y+3)^2=(y+3)(y+3)\)?

Oh, and it should be \((y-3)^2=(y-3)(y-3)\). Oops :(

\[\left( y+3 \right)\left( y+3 \right)\]
\[y^{2}+3y+3y+9?\]

yes i can. Thank you soo much king. for every thing. ima fan you

You're welcome. Feel free to post what you get as solutions and I can check them if you want.

kk will do. Thanks