## haterofmath Group Title What hapeens if the limit is being taken from the left? one year ago one year ago

1. across Group Title

Anything can happen, but generally, you're approaching the limit point from negative infinity.

2. haterofmath Group Title

so in a problem such as $\lim_{x \rightarrow 2-}\frac{ x^2+4 }{ x-2 }$ howw would it work?

3. helder_edwin Group Title

since $$x\to2-$$ then $$x<2$$ so $$x-2<0$$

4. helder_edwin Group Title

this means that $\Large \lim_{x\to2-}\frac{x^2+4}{x-2}=-\infty$

5. haterofmath Group Title

ok, so i won't have to plug anything in?

6. haterofmath Group Title

and if it were moving to the right it would be $+\infty$

7. helder_edwin Group Title

well, pluging in you would have $\Large \frac{2^2+4}{2-2}=\frac{8}{0}$

8. helder_edwin Group Title

yes. if $$x\to2+$$ then $$x>2$$ so $$x-2>0$$

9. pradipgr817 Group Title

I have tried it differently |dw:1347746473941:dw| at left as h tends 0 x tends$2^{-}$

10. pradipgr817 Group Title

so if we replace x by 2-h and let h tends to 0 then there will be a different solution.

11. haterofmath Group Title

and what solutions that?

12. pradipgr817 Group Title

you can put it and find it.