anonymous
  • anonymous
What hapeens if the limit is being taken from the left?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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across
  • across
Anything can happen, but generally, you're approaching the limit point from negative infinity.
anonymous
  • anonymous
so in a problem such as \[\lim_{x \rightarrow 2-}\frac{ x^2+4 }{ x-2 }\] howw would it work?
helder_edwin
  • helder_edwin
since \(x\to2-\) then \(x<2\) so \(x-2<0\)

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helder_edwin
  • helder_edwin
this means that \[ \Large \lim_{x\to2-}\frac{x^2+4}{x-2}=-\infty \]
anonymous
  • anonymous
ok, so i won't have to plug anything in?
anonymous
  • anonymous
and if it were moving to the right it would be \[+\infty\]
helder_edwin
  • helder_edwin
well, pluging in you would have \[ \Large \frac{2^2+4}{2-2}=\frac{8}{0} \]
helder_edwin
  • helder_edwin
yes. if \(x\to2+\) then \(x>2\) so \(x-2>0\)
pradipgr817
  • pradipgr817
I have tried it differently |dw:1347746473941:dw| at left as h tends 0 x tends\[2^{-}\]
pradipgr817
  • pradipgr817
so if we replace x by 2-h and let h tends to 0 then there will be a different solution.
anonymous
  • anonymous
and what solutions that?
pradipgr817
  • pradipgr817
you can put it and find it.

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