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## anonymous 3 years ago What hapeens if the limit is being taken from the left?

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1. across

Anything can happen, but generally, you're approaching the limit point from negative infinity.

2. anonymous

so in a problem such as $\lim_{x \rightarrow 2-}\frac{ x^2+4 }{ x-2 }$ howw would it work?

3. helder_edwin

since $$x\to2-$$ then $$x<2$$ so $$x-2<0$$

4. helder_edwin

this means that $\Large \lim_{x\to2-}\frac{x^2+4}{x-2}=-\infty$

5. anonymous

ok, so i won't have to plug anything in?

6. anonymous

and if it were moving to the right it would be $+\infty$

7. helder_edwin

well, pluging in you would have $\Large \frac{2^2+4}{2-2}=\frac{8}{0}$

8. helder_edwin

yes. if $$x\to2+$$ then $$x>2$$ so $$x-2>0$$

9. anonymous

I have tried it differently |dw:1347746473941:dw| at left as h tends 0 x tends$2^{-}$

10. anonymous

so if we replace x by 2-h and let h tends to 0 then there will be a different solution.

11. anonymous

and what solutions that?

12. anonymous

you can put it and find it.

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