## luisz Group Title In the figure above, ED=EC, the area of square ABCD is 100, and the area of triangle DEC is 10. Find the distance from A to E one year ago one year ago

1. luisz Group Title

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2. luisz Group Title

ABCDE

3. luisz Group Title

I know that a side of the square is 10

4. luisz Group Title

So DC equals 10

5. luisz Group Title

6. luisz Group Title

I do not know what DE equals, though

7. ganeshie8 Group Title

|dw:1347747747441:dw|

8. luisz Group Title

hmm

9. luisz Group Title

Are you trying to form a right triangle?

10. luisz Group Title

IF you are, one side would equal 5

11. luisz Group Title

So the height of the smaller triangle equals 2

12. luisz Group Title

do you add 10 plus 2?

13. KingGeorge Group Title

You beat me to the height. nice job. But you don't add them yet.

14. luisz Group Title

ok

15. luisz Group Title

well one side is 5

16. luisz Group Title

another side is 10 plus 2...

17. KingGeorge Group Title

|dw:1347747944748:dw|You need to find the length of x in this.

18. luisz Group Title

so do you use pythagorean theorem?

19. luisz Group Title

x in that would be square root of 29

20. luisz Group Title

if you use pythagorean theorem

21. KingGeorge Group Title

Right. So that means that DE=$$\sqrt{29}$$ and AD=10.

22. luisz Group Title

12 squared plus 5 squared=169

23. luisz Group Title

square root of 169 is 13

24. luisz Group Title

x=13?

25. KingGeorge Group Title

Oh, yes. I was thinking of the wrong distance. That's correct.

26. luisz Group Title

yes!!!!!