anonymous
  • anonymous
In the figure above, ED=EC, the area of square ABCD is 100, and the area of triangle DEC is 10. Find the distance from A to E
Mathematics
katieb
  • katieb
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anonymous
  • anonymous
|dw:1347747550774:dw|
anonymous
  • anonymous
ABCDE
anonymous
  • anonymous
I know that a side of the square is 10

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anonymous
  • anonymous
So DC equals 10
anonymous
  • anonymous
So AD equals 10
anonymous
  • anonymous
I do not know what DE equals, though
ganeshie8
  • ganeshie8
|dw:1347747747441:dw|
anonymous
  • anonymous
hmm
anonymous
  • anonymous
Are you trying to form a right triangle?
anonymous
  • anonymous
IF you are, one side would equal 5
anonymous
  • anonymous
So the height of the smaller triangle equals 2
anonymous
  • anonymous
do you add 10 plus 2?
KingGeorge
  • KingGeorge
You beat me to the height. nice job. But you don't add them yet.
anonymous
  • anonymous
ok
anonymous
  • anonymous
well one side is 5
anonymous
  • anonymous
another side is 10 plus 2...
KingGeorge
  • KingGeorge
|dw:1347747944748:dw|You need to find the length of x in this.
anonymous
  • anonymous
so do you use pythagorean theorem?
anonymous
  • anonymous
x in that would be square root of 29
anonymous
  • anonymous
if you use pythagorean theorem
KingGeorge
  • KingGeorge
Right. So that means that DE=\(\sqrt{29}\) and AD=10.
anonymous
  • anonymous
12 squared plus 5 squared=169
anonymous
  • anonymous
square root of 169 is 13
anonymous
  • anonymous
x=13?
KingGeorge
  • KingGeorge
Oh, yes. I was thinking of the wrong distance. That's correct.
anonymous
  • anonymous
yes!!!!!

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