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luisz

  • 3 years ago

In the figure above, ED=EC, the area of square ABCD is 100, and the area of triangle DEC is 10. Find the distance from A to E

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  1. luisz
    • 3 years ago
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    |dw:1347747550774:dw|

  2. luisz
    • 3 years ago
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    ABCDE

  3. luisz
    • 3 years ago
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    I know that a side of the square is 10

  4. luisz
    • 3 years ago
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    So DC equals 10

  5. luisz
    • 3 years ago
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    So AD equals 10

  6. luisz
    • 3 years ago
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    I do not know what DE equals, though

  7. ganeshie8
    • 3 years ago
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    |dw:1347747747441:dw|

  8. luisz
    • 3 years ago
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    hmm

  9. luisz
    • 3 years ago
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    Are you trying to form a right triangle?

  10. luisz
    • 3 years ago
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    IF you are, one side would equal 5

  11. luisz
    • 3 years ago
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    So the height of the smaller triangle equals 2

  12. luisz
    • 3 years ago
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    do you add 10 plus 2?

  13. KingGeorge
    • 3 years ago
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    You beat me to the height. nice job. But you don't add them yet.

  14. luisz
    • 3 years ago
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    ok

  15. luisz
    • 3 years ago
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    well one side is 5

  16. luisz
    • 3 years ago
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    another side is 10 plus 2...

  17. KingGeorge
    • 3 years ago
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    |dw:1347747944748:dw|You need to find the length of x in this.

  18. luisz
    • 3 years ago
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    so do you use pythagorean theorem?

  19. luisz
    • 3 years ago
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    x in that would be square root of 29

  20. luisz
    • 3 years ago
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    if you use pythagorean theorem

  21. KingGeorge
    • 3 years ago
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    Right. So that means that DE=\(\sqrt{29}\) and AD=10.

  22. luisz
    • 3 years ago
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    12 squared plus 5 squared=169

  23. luisz
    • 3 years ago
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    square root of 169 is 13

  24. luisz
    • 3 years ago
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    x=13?

  25. KingGeorge
    • 3 years ago
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    Oh, yes. I was thinking of the wrong distance. That's correct.

  26. luisz
    • 3 years ago
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    yes!!!!!

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