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luisz

In the figure above, ED=EC, the area of square ABCD is 100, and the area of triangle DEC is 10. Find the distance from A to E

  • one year ago
  • one year ago

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  1. luisz
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    |dw:1347747550774:dw|

    • one year ago
  2. luisz
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    ABCDE

    • one year ago
  3. luisz
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    I know that a side of the square is 10

    • one year ago
  4. luisz
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    So DC equals 10

    • one year ago
  5. luisz
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    So AD equals 10

    • one year ago
  6. luisz
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    I do not know what DE equals, though

    • one year ago
  7. ganeshie8
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    |dw:1347747747441:dw|

    • one year ago
  8. luisz
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    hmm

    • one year ago
  9. luisz
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    Are you trying to form a right triangle?

    • one year ago
  10. luisz
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    IF you are, one side would equal 5

    • one year ago
  11. luisz
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    So the height of the smaller triangle equals 2

    • one year ago
  12. luisz
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    do you add 10 plus 2?

    • one year ago
  13. KingGeorge
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    You beat me to the height. nice job. But you don't add them yet.

    • one year ago
  14. luisz
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    ok

    • one year ago
  15. luisz
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    well one side is 5

    • one year ago
  16. luisz
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    another side is 10 plus 2...

    • one year ago
  17. KingGeorge
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    |dw:1347747944748:dw|You need to find the length of x in this.

    • one year ago
  18. luisz
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    so do you use pythagorean theorem?

    • one year ago
  19. luisz
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    x in that would be square root of 29

    • one year ago
  20. luisz
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    if you use pythagorean theorem

    • one year ago
  21. KingGeorge
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    Right. So that means that DE=\(\sqrt{29}\) and AD=10.

    • one year ago
  22. luisz
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    12 squared plus 5 squared=169

    • one year ago
  23. luisz
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    square root of 169 is 13

    • one year ago
  24. luisz
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    x=13?

    • one year ago
  25. KingGeorge
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    Oh, yes. I was thinking of the wrong distance. That's correct.

    • one year ago
  26. luisz
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    yes!!!!!

    • one year ago
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