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luisz
 3 years ago
In the figure above, ED=EC, the area of square ABCD
is 100, and the area of triangle DEC is 10. Find
the distance from A to E
luisz
 3 years ago
In the figure above, ED=EC, the area of square ABCD is 100, and the area of triangle DEC is 10. Find the distance from A to E

This Question is Closed

luisz
 3 years ago
Best ResponseYou've already chosen the best response.1I know that a side of the square is 10

luisz
 3 years ago
Best ResponseYou've already chosen the best response.1I do not know what DE equals, though

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1347747747441:dw

luisz
 3 years ago
Best ResponseYou've already chosen the best response.1Are you trying to form a right triangle?

luisz
 3 years ago
Best ResponseYou've already chosen the best response.1IF you are, one side would equal 5

luisz
 3 years ago
Best ResponseYou've already chosen the best response.1So the height of the smaller triangle equals 2

KingGeorge
 3 years ago
Best ResponseYou've already chosen the best response.1You beat me to the height. nice job. But you don't add them yet.

luisz
 3 years ago
Best ResponseYou've already chosen the best response.1another side is 10 plus 2...

KingGeorge
 3 years ago
Best ResponseYou've already chosen the best response.1dw:1347747944748:dwYou need to find the length of x in this.

luisz
 3 years ago
Best ResponseYou've already chosen the best response.1so do you use pythagorean theorem?

luisz
 3 years ago
Best ResponseYou've already chosen the best response.1x in that would be square root of 29

luisz
 3 years ago
Best ResponseYou've already chosen the best response.1if you use pythagorean theorem

KingGeorge
 3 years ago
Best ResponseYou've already chosen the best response.1Right. So that means that DE=\(\sqrt{29}\) and AD=10.

luisz
 3 years ago
Best ResponseYou've already chosen the best response.112 squared plus 5 squared=169

KingGeorge
 3 years ago
Best ResponseYou've already chosen the best response.1Oh, yes. I was thinking of the wrong distance. That's correct.
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