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your y_c is wrong

it's -1

typo

mah bad...

it should be \[y_c = c_1 e^{-x} + c_2 x e^{-x}\]
see your mistake?

yeah r=-1

i was actually referring to the x by c2

if you have repeated roots you attach least power of x to the next arbitrary constant, remember?

oh I'm sorry I see it now

so do you know what y_p should be now?

what does that have to do with y_p? isn't y_p based on what the RHS of the original equation is?

are you using undetermined coefficients or variation of parameters>

I don't quite know what either of those mean, but I trying to do it based on \[y_p=Ae^{bx}\]

please don't shoot me :S

I'm willing to learn =)

can you describe to me the method you're familiar with?
does it involve deriving the yp?

according to my book I'm doing it based on THE METHOD OF UNDETERMINED COEFFICIENTS

oh that

does that make sense?

yes. that. but in this case, we're doing y_p

\[y_p=Ae^{-x}+Bxe^{-x}\]

and then I just do the derivative twice to solve for A and B

sounds right

thank ya!

welcome

y ' =-Ae^(-x) -(x-1)Be^(-x)
you have an extra x in there..

oh I see

ok I'll try it again

I still get a zero for x....I'll show my work, give me a second to type it :)

Hold up.

I think you need a C*x^2*e-x term as part of your solution...

e-x?

e^(-x)?

Why a
\[Cx^2e^{-x}\]
?

I think I'm gonna start a new thread. This one is getting too long

Hope that helps; probably not, but I tried:)

Yeah It kinda makes sense.