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haterofmath Group TitleBest ResponseYou've already chosen the best response.0
\[y=17; x _{0}=3\]
 one year ago

daru Group TitleBest ResponseYou've already chosen the best response.0
If the function is the constant function y = 17, then the derivative of it (dy/dx) is simply 0. The derivative of any constant is "0". Remember that "derivative" means "the change y with respect to x" in this case. If y = 7 at all points, then it never changes with respect to x. Therefore, the change is 0.
 one year ago

haterofmath Group TitleBest ResponseYou've already chosen the best response.0
so what do you do with the 3
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
there has to be more to this question which you have not given us
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
if the equation for y is simply: y = 17 .. then daru is correct.
 one year ago

haterofmath Group TitleBest ResponseYou've already chosen the best response.0
sorry wrong problem \[y=62x; x_{0}=3\]
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
first step, is to take the derivative of y, but the method of that step differs depending on how youre spose to go about it. there is a first principals method, and the derivative rules method. Which method have you been doing in your lessons?
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
derivative rules are much easier to work with then; what derivative rule would you say can apply to this question?
 one year ago

haterofmath Group TitleBest ResponseYou've already chosen the best response.0
wouldn't the derivative be 2
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
almost, that negative sign (subtraction) needs to be recognized :) y= 6  2x y' = 6'  (2x)' = 0  2
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
now, since there is no place to plug in the value of x in the derivative; the value of the derivative at ANY point is: 2
 one year ago

haterofmath Group TitleBest ResponseYou've already chosen the best response.0
oh ok.
 one year ago

haterofmath Group TitleBest ResponseYou've already chosen the best response.0
/so how do you find that slope of tangent after taking the derivative?
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
the value of the derivative DEFINES the slope of the tangent at a given point.
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
in this case, 6  2x is a straight line whose sloe is 2 at all points
 one year ago

haterofmath Group TitleBest ResponseYou've already chosen the best response.0
so in a problem such as f(x)=5x3 the slope of the line that is tangent is 5?
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
the more complicated the curve, the less trivial the derivative becomes :) take: y=x^2 y' = 2x the slope at any given point of y=x^2 is defined as 2x the slope at x=3 would be 2(3) = 6 the slope at x=7 would be 2(7) = 14 the slope at x=2 would be 2(2) = 4
 one year ago

haterofmath Group TitleBest ResponseYou've already chosen the best response.0
ok. thanks
 one year ago
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