An easy math question.Lets see who solves it first. 120-->9-->3 130-->8-->2 140-->7-->? 150-->6-->0

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An easy math question.Lets see who solves it first. 120-->9-->3 130-->8-->2 140-->7-->? 150-->6-->0

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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nopes,not 1.
7
no!

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Other answers:

lol ;)
0?
4?
yes, it is 0.message me logic.let others try.
@siddhantsharan got it correct :)
:)
but ho did u find 0 @siddhantsharan ????? Plz tell us :)
is it that all the 120,130, 140, and 150 end at zero
Oh i got it too
no, not that logic... and let others try for some time tooo....
I could. But that would ruin it for others.
160--->5---->0
right?
@sauravshakya message me logic
9-8 is 1 & 7-6 is 1 and then 1-1 is 0
is 0 the only number that you can't divide by 7
what about 120,130,140.... then ??
2 people got it correct till now.
ok, i m giving out the logic now...
its the remainder.! when 140 is divided by 7, the remainder is 0.
but @ hartnn what is the logic before 120--->9----->3 & etc. ?????
logic before ?? 120 when divide by 9 gives remainder 3.
& 130 ----> 8 -----> 2
same logic! 130 when divided by 8 gives remainder 2
ohh ! i gt it :) Thanx a lot :)
welcome :)

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