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amishra

  • 3 years ago

Solve for x: (e as in logs) a) 3e^x -5 = -2e^-x b) 2ln x - 3ln(1/x) =10

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  1. chandhuru
    • 3 years ago
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    |dw:1347804062395:dw| is this the ques ????

  2. Jonask
    • 3 years ago
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    multiply by e^x and let it be k

  3. chandhuru
    • 3 years ago
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    for second one use ln(1/a) = - ln(a)

  4. Jonask
    • 3 years ago
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    \[3(e^{x})^2-5e^x=-2\] \[3k^2-5k+2=0\]

  5. amishra
    • 3 years ago
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    @Jonask , what? Can you rephrase? @chandhuru , yes, thats the question. :)

  6. chandhuru
    • 3 years ago
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    hmmm.. then

  7. chandhuru
    • 3 years ago
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    |dw:1347804343788:dw| take LCM you will get a quadratic eqn solve it

  8. chandhuru
    • 3 years ago
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    |dw:1347804503096:dw| solve this quadratic eqn...

  9. amishra
    • 3 years ago
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    how did you get this?

  10. chandhuru
    • 3 years ago
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    i should u steps ...see the steps listed above..

  11. amishra
    • 3 years ago
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    I am sorry, I didn't get it :/

  12. chandhuru
    • 3 years ago
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    which step u dont understand????

  13. amishra
    • 3 years ago
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    OKay, got it, can you tell me the second one?

  14. chandhuru
    • 3 years ago
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    use the formula ln(1/a) = - ln(a)

  15. amishra
    • 3 years ago
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    lemme try :)

  16. chandhuru
    • 3 years ago
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    got it ah????

  17. amishra
    • 3 years ago
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    No, can you please show the steps?

  18. chandhuru
    • 3 years ago
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    ok..

  19. chandhuru
    • 3 years ago
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    |dw:1347805590065:dw| now solve it...

  20. chandhuru
    • 3 years ago
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    got it ???

  21. amishra
    • 3 years ago
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    Oh! I got it!! Thank you! :D Soo much!

  22. chandhuru
    • 3 years ago
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    ok.. welcome..

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