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amishra Group Title

Solve for x: (e as in logs) a) 3e^x -5 = -2e^-x b) 2ln x - 3ln(1/x) =10

  • one year ago
  • one year ago

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  1. chandhuru Group Title
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    |dw:1347804062395:dw| is this the ques ????

    • one year ago
  2. Jonask Group Title
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    multiply by e^x and let it be k

    • one year ago
  3. chandhuru Group Title
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    for second one use ln(1/a) = - ln(a)

    • one year ago
  4. Jonask Group Title
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    \[3(e^{x})^2-5e^x=-2\] \[3k^2-5k+2=0\]

    • one year ago
  5. amishra Group Title
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    @Jonask , what? Can you rephrase? @chandhuru , yes, thats the question. :)

    • one year ago
  6. chandhuru Group Title
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    hmmm.. then

    • one year ago
  7. chandhuru Group Title
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    |dw:1347804343788:dw| take LCM you will get a quadratic eqn solve it

    • one year ago
  8. chandhuru Group Title
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    |dw:1347804503096:dw| solve this quadratic eqn...

    • one year ago
  9. amishra Group Title
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    how did you get this?

    • one year ago
  10. chandhuru Group Title
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    i should u steps ...see the steps listed above..

    • one year ago
  11. amishra Group Title
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    I am sorry, I didn't get it :/

    • one year ago
  12. chandhuru Group Title
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    which step u dont understand????

    • one year ago
  13. amishra Group Title
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    OKay, got it, can you tell me the second one?

    • one year ago
  14. chandhuru Group Title
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    use the formula ln(1/a) = - ln(a)

    • one year ago
  15. amishra Group Title
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    lemme try :)

    • one year ago
  16. chandhuru Group Title
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    got it ah????

    • one year ago
  17. amishra Group Title
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    No, can you please show the steps?

    • one year ago
  18. chandhuru Group Title
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    ok..

    • one year ago
  19. chandhuru Group Title
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    |dw:1347805590065:dw| now solve it...

    • one year ago
  20. chandhuru Group Title
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    got it ???

    • one year ago
  21. amishra Group Title
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    Oh! I got it!! Thank you! :D Soo much!

    • one year ago
  22. chandhuru Group Title
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    ok.. welcome..

    • one year ago
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