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amishra

  • 3 years ago

Solve for x: (e is part of logs) e^x + e^-x =3

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  1. erica.d
    • 3 years ago
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    e^x=y

  2. erica.d
    • 3 years ago
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    y^2-3y+1=0 solve for y

  3. erica.d
    • 3 years ago
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    i had solved this question when i was in sixth grade....this is fun lol :)

  4. amishra
    • 3 years ago
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    How did you get 1?

  5. cinar
    • 3 years ago
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    |dw:1347814545665:dw|

  6. erica.d
    • 3 years ago
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    \[y+\frac{ 1 }{ y }=3......y^2+1=3y\]

  7. erica.d
    • 3 years ago
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    does that help you?

  8. amishra
    • 3 years ago
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    I am not getting the answer, can you show me?

  9. erica.d
    • 3 years ago
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    well i was told to simplify it by quadratic i don't know further :p sorry lol y^2-3y+1=0

  10. amishra
    • 3 years ago
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    I didn't get the answer :/

  11. cinar
    • 3 years ago
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    http://www.wolframalpha.com/input/?i=solve+y^2-3y%2B1%3D0

  12. cinar
    • 3 years ago
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    x=ln(0.381966) x=ln( 2.61803) solutions..

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