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kmalone99Best ResponseYou've already chosen the best response.0
x+3y=3 substrct x from both sides what would you get?
 one year ago

katiebuggBest ResponseYou've already chosen the best response.0
id set them both equal to y then solve like that
 one year ago

kmalone99Best ResponseYou've already chosen the best response.0
ar you can sub y=1/3x+2 in to other equation x+3(1/3 x+x)=3 solve for x
 one year ago

yummydumBest ResponseYou've already chosen the best response.2
since y equals 1/3x+2 we can substitute that into the second equation like this:\[x+3(1/3 x+2)=3\]and then solve for x:\[x3x+6=3\]\[2x+6=3\]\[2x=3\]\[x=3/2\] now substitute this x into the first equation:\[y=1/3(3/2)+2\]\[y=1/2+2\]\[y=5/2\] \[{x=3/2~~~~~~~~y=5/2}\]
 one year ago

trentsellarsBest ResponseYou've already chosen the best response.0
okay I see the first part. but the problem with 5/2, is that thats not one of the answer options. but 3/2, 0 is
 one year ago

yummydumBest ResponseYou've already chosen the best response.2
\[x+3(−1/3x+2)=3\] and then solve for x: \[x−x+6=3\]\[0x+6=3\]\[0x=−3\]\[x=0\] now substitute this x into the first equation: \[y=−1/3(0)+2\]\[y=0+2\]\[y=2\] \[x=0~~~y=2\]
 one year ago

yummydumBest ResponseYou've already chosen the best response.2
is that one of the choices? sorry i did that wrong but i fixed it...helpful? :)
 one year ago

trentsellarsBest ResponseYou've already chosen the best response.0
(0, 1) (1, 0) (3, 1/3) (3/2, 0) these are the options.
 one year ago

yummydumBest ResponseYou've already chosen the best response.2
y has to equal 1 when x is 0
 one year ago

jim_thompson5910Best ResponseYou've already chosen the best response.0
yummydum, if 0x=−3, then 0 = 3 which is a contradiction So there are no solutions.
 one year ago

kmalone99Best ResponseYou've already chosen the best response.0
besides the mistake then you .. wait if you have choses then the order pair are (x,y) sub into the equations example take the first one 0,1 y= 1/3 + 2 and x + 3y = 3 1=1/3(0)+2 and 0+3(1)=3 1=2 not a solutation and 3=3 solves right equations so do the next set of pairs and tell me what you find out
 one year ago

trentsellarsBest ResponseYou've already chosen the best response.0
damn im confused...
 one year ago

kmalone99Best ResponseYou've already chosen the best response.0
is that all the possiablities? there is no solutions be these are parallal lines
 one year ago

kmalone99Best ResponseYou've already chosen the best response.0
sorry your confused but it says solve so look at what we have sub the points in the equations and see if it equals or solve for x or y and then find what you did nt solve for... do you understand this
 one year ago

trentsellarsBest ResponseYou've already chosen the best response.0
there is a no solution
 one year ago

jim_thompson5910Best ResponseYou've already chosen the best response.0
i would be confused too...the answer choices are incorrect because the true answer is "no solution" or "there is/are no solution(s)"
 one year ago

jim_thompson5910Best ResponseYou've already chosen the best response.0
so there must be a typo somewhere
 one year ago

kmalone99Best ResponseYou've already chosen the best response.0
there is your answer but do you understand why?
 one year ago

kmalone99Best ResponseYou've already chosen the best response.0
i think i got this jim_thompson5910
 one year ago

trentsellarsBest ResponseYou've already chosen the best response.0
yeah i do thanks :)
 one year ago

kmalone99Best ResponseYou've already chosen the best response.0
great you also can see let equations equal 1/3 x+2=1/3 x+1and solve for x then you get 2=1 so no solution. :)
 one year ago

phiBest ResponseYou've already chosen the best response.0
another way to look at \[y= \frac{1}{3}x + 2 \text { and } x + 3y = 3\] the 2nd equation, after rearranging into y= mx+b form is \[ y= \frac{1}{3}x+3\] You have two lines that are parallel, and never meet. There is no (x,y) pair that is on both lines (as would be the case if they intersected)
 one year ago

kmalone99Best ResponseYou've already chosen the best response.0
already said this phi
 one year ago
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