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I know the perimeter is 40 because each side of MNOP is 10
I came to that conclusion because of 6-8-10 right triangle
so why is the area 96 and not 100?
isn't each side of quadrilateral MNOP 10?
Can you list out the lengths you're given please?
MB is 8 and BN is 6
I am assuming MN is 10 because of the 3-4-5 triangle rule
That's right. Are you given more information?
I assume this quad to be a square
the perimeter is 40
but I may be wrong
since the area is 96;not 100
I think you're supposed to assume that each side length is 10. However, this does not mean it's a square. For example:|dw:1347833088897:dw|This quadrilateral actually has an area of 50. Remember that you need to multiply by the height, and the height may be different than the side length.
the answer is 96 for area
and I am talking about quad MNOP
Just bear with me for a second. That was just an example to show that having side lengths of 10, doesn't imply that the area is 100.
What I would do, is assume that all the triangles in your problem are congruent. Thus, you find the area of ABCD, and subtract 4*area of MBN. Does this make more sense?
12 times 16=192?
I sorta understand that
You find the whole area and subtract the part that interferes with MNOP
Right. Are you getting 96 now?
how did you get the height of the triangle?