What is the area of quadrilateral MNOP?

- anonymous

What is the area of quadrilateral MNOP?

- schrodinger

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- anonymous

|dw:1347832465830:dw|

- anonymous

tips?

- anonymous

I know the perimeter is 40 because each side of MNOP is 10

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## More answers

- anonymous

I came to that conclusion because of 6-8-10 right triangle

- anonymous

so why is the area 96 and not 100?

- anonymous

isn't each side of quadrilateral MNOP 10?

- KingGeorge

Can you list out the lengths you're given please?

- anonymous

MB is 8 and BN is 6

- anonymous

I am assuming MN is 10 because of the 3-4-5 triangle rule

- KingGeorge

That's right. Are you given more information?

- anonymous

no

- anonymous

I assume this quad to be a square

- anonymous

the perimeter is 40

- anonymous

10+10+10+10

- anonymous

but I may be wrong

- anonymous

since the area is 96;not 100

- KingGeorge

I think you're supposed to assume that each side length is 10. However, this does not mean it's a square. For example:|dw:1347833088897:dw|This quadrilateral actually has an area of 50. Remember that you need to multiply by the height, and the height may be different than the side length.

- anonymous

ehh

- anonymous

the answer is 96 for area

- anonymous

and I am talking about quad MNOP

- anonymous

Not ABCD

- KingGeorge

Just bear with me for a second. That was just an example to show that having side lengths of 10, doesn't imply that the area is 100.

- anonymous

ahh

- anonymous

I see

- anonymous

shh

- anonymous

ahh

- KingGeorge

What I would do, is assume that all the triangles in your problem are congruent. Thus, you find the area of ABCD, and subtract 4*area of MBN. Does this make more sense?

- anonymous

yeah

- anonymous

so

- anonymous

12 times 16=192?

- anonymous

k

- anonymous

192-96=96?

- anonymous

I sorta understand that

- anonymous

You find the whole area and subtract the part that interferes with MNOP

- anonymous

ty

- KingGeorge

Right. Are you getting 96 now?

- anonymous

yeppers

- anonymous

192-96=96

- anonymous

how did you get the height of the triangle?

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