A community for students. Sign up today!
Here's the question you clicked on:
 0 viewing

This Question is Closed

shashi20008
 2 years ago
Best ResponseYou've already chosen the best response.1yeah sure, \[\frac{ d}{ dx }(2x5x ^{2})\] \[=\frac{ d}{ dx }(2x)\frac{ d}{ dx }(5x ^{2})\] \[=2  5\frac{ d }{ dx }(x ^{2})\] \[=2  5 * 2x\] \[= 2 5x\]

JayCT
 2 years ago
Best ResponseYou've already chosen the best response.0ok thx very much. i have another one similar f(t)= 2t^2  sqrt(t^3)

shashi20008
 2 years ago
Best ResponseYou've already chosen the best response.1its quite similar, you have to do same thing. simply remember, while differentiating some variable exponent some constant number, you just have to multiply the exponent to coefficient of the term and then write the variable after decreasing the exponent by one. Do this for each term in an expression and you would be done :) as for your ques, \[f'(x) = \frac{ d }{ dx }(2t ^{2}  \sqrt{t ^{3}})\] \[= \frac{ d }{ dx }(2t ^{2})  \frac{ d }{ dx }(\sqrt{t ^{3}})\] \[=2 \frac{ d }{ dx }(t ^{2})  \frac{ d }{ dx }(t ^{\frac{ 3 }{ 2 }})\] \[=2 *2t  \frac{ 3 }{ 2 }(t ^{\frac{ 1 }{ 2 }})\] \[=4t  \frac{ 3 }{ 2 }(\sqrt{t})\]

JayCT
 2 years ago
Best ResponseYou've already chosen the best response.0wow thanks very much. i have few other questions, dont know if you would mind helping me?
Ask your own question
Ask a QuestionFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.