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JayCT

  • 2 years ago

find the derivative of 2x -5sqrt(x) using rules of differentiations please

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  1. shashi20008
    • 2 years ago
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    2 - 10x

  2. JayCT
    • 2 years ago
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    can you show steps pls

  3. shashi20008
    • 2 years ago
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    yeah sure, \[\frac{ d}{ dx }(2x-5x ^{2})\] \[=\frac{ d}{ dx }(2x)-\frac{ d}{ dx }(5x ^{2})\] \[=2 - 5\frac{ d }{ dx }(x ^{2})\] \[=2 - 5 * 2x\] \[= 2- 5x\]

  4. JayCT
    • 2 years ago
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    ok thx very much. i have another one similar f(t)= 2t^2 - sqrt(t^3)

  5. shashi20008
    • 2 years ago
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    its quite similar, you have to do same thing. simply remember, while differentiating some variable exponent some constant number, you just have to multiply the exponent to coefficient of the term and then write the variable after decreasing the exponent by one. Do this for each term in an expression and you would be done :) as for your ques, \[f'(x) = \frac{ d }{ dx }(2t ^{2} - \sqrt{t ^{3}})\] \[= \frac{ d }{ dx }(2t ^{2}) - \frac{ d }{ dx }(\sqrt{t ^{3}})\] \[=2 \frac{ d }{ dx }(t ^{2}) - \frac{ d }{ dx }(t ^{\frac{ 3 }{ 2 }})\] \[=2 *2t - \frac{ 3 }{ 2 }(t ^{\frac{ 1 }{ 2 }})\] \[=4t - \frac{ 3 }{ 2 }(\sqrt{t})\]

  6. JayCT
    • 2 years ago
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    wow thanks very much. i have few other questions, dont know if you would mind helping me?

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