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anonymous
 4 years ago
find the derivative of 2x 5sqrt(x) using rules of differentiations please
anonymous
 4 years ago
find the derivative of 2x 5sqrt(x) using rules of differentiations please

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0can you show steps pls

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yeah sure, \[\frac{ d}{ dx }(2x5x ^{2})\] \[=\frac{ d}{ dx }(2x)\frac{ d}{ dx }(5x ^{2})\] \[=2  5\frac{ d }{ dx }(x ^{2})\] \[=2  5 * 2x\] \[= 2 5x\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok thx very much. i have another one similar f(t)= 2t^2  sqrt(t^3)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0its quite similar, you have to do same thing. simply remember, while differentiating some variable exponent some constant number, you just have to multiply the exponent to coefficient of the term and then write the variable after decreasing the exponent by one. Do this for each term in an expression and you would be done :) as for your ques, \[f'(x) = \frac{ d }{ dx }(2t ^{2}  \sqrt{t ^{3}})\] \[= \frac{ d }{ dx }(2t ^{2})  \frac{ d }{ dx }(\sqrt{t ^{3}})\] \[=2 \frac{ d }{ dx }(t ^{2})  \frac{ d }{ dx }(t ^{\frac{ 3 }{ 2 }})\] \[=2 *2t  \frac{ 3 }{ 2 }(t ^{\frac{ 1 }{ 2 }})\] \[=4t  \frac{ 3 }{ 2 }(\sqrt{t})\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0wow thanks very much. i have few other questions, dont know if you would mind helping me?
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