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JayCT
Group Title
find the derivative of 2x 5sqrt(x) using rules of differentiations please
 2 years ago
 2 years ago
JayCT Group Title
find the derivative of 2x 5sqrt(x) using rules of differentiations please
 2 years ago
 2 years ago

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shashi20008 Group TitleBest ResponseYou've already chosen the best response.1
2  10x
 2 years ago

JayCT Group TitleBest ResponseYou've already chosen the best response.0
can you show steps pls
 2 years ago

shashi20008 Group TitleBest ResponseYou've already chosen the best response.1
yeah sure, \[\frac{ d}{ dx }(2x5x ^{2})\] \[=\frac{ d}{ dx }(2x)\frac{ d}{ dx }(5x ^{2})\] \[=2  5\frac{ d }{ dx }(x ^{2})\] \[=2  5 * 2x\] \[= 2 5x\]
 2 years ago

JayCT Group TitleBest ResponseYou've already chosen the best response.0
ok thx very much. i have another one similar f(t)= 2t^2  sqrt(t^3)
 2 years ago

shashi20008 Group TitleBest ResponseYou've already chosen the best response.1
its quite similar, you have to do same thing. simply remember, while differentiating some variable exponent some constant number, you just have to multiply the exponent to coefficient of the term and then write the variable after decreasing the exponent by one. Do this for each term in an expression and you would be done :) as for your ques, \[f'(x) = \frac{ d }{ dx }(2t ^{2}  \sqrt{t ^{3}})\] \[= \frac{ d }{ dx }(2t ^{2})  \frac{ d }{ dx }(\sqrt{t ^{3}})\] \[=2 \frac{ d }{ dx }(t ^{2})  \frac{ d }{ dx }(t ^{\frac{ 3 }{ 2 }})\] \[=2 *2t  \frac{ 3 }{ 2 }(t ^{\frac{ 1 }{ 2 }})\] \[=4t  \frac{ 3 }{ 2 }(\sqrt{t})\]
 2 years ago

JayCT Group TitleBest ResponseYou've already chosen the best response.0
wow thanks very much. i have few other questions, dont know if you would mind helping me?
 2 years ago
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