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JayCT
Group Title
find the derivative of 2x 5sqrt(x) using rules of differentiations please
 one year ago
 one year ago
JayCT Group Title
find the derivative of 2x 5sqrt(x) using rules of differentiations please
 one year ago
 one year ago

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shashi20008 Group TitleBest ResponseYou've already chosen the best response.1
2  10x
 one year ago

JayCT Group TitleBest ResponseYou've already chosen the best response.0
can you show steps pls
 one year ago

shashi20008 Group TitleBest ResponseYou've already chosen the best response.1
yeah sure, \[\frac{ d}{ dx }(2x5x ^{2})\] \[=\frac{ d}{ dx }(2x)\frac{ d}{ dx }(5x ^{2})\] \[=2  5\frac{ d }{ dx }(x ^{2})\] \[=2  5 * 2x\] \[= 2 5x\]
 one year ago

JayCT Group TitleBest ResponseYou've already chosen the best response.0
ok thx very much. i have another one similar f(t)= 2t^2  sqrt(t^3)
 one year ago

shashi20008 Group TitleBest ResponseYou've already chosen the best response.1
its quite similar, you have to do same thing. simply remember, while differentiating some variable exponent some constant number, you just have to multiply the exponent to coefficient of the term and then write the variable after decreasing the exponent by one. Do this for each term in an expression and you would be done :) as for your ques, \[f'(x) = \frac{ d }{ dx }(2t ^{2}  \sqrt{t ^{3}})\] \[= \frac{ d }{ dx }(2t ^{2})  \frac{ d }{ dx }(\sqrt{t ^{3}})\] \[=2 \frac{ d }{ dx }(t ^{2})  \frac{ d }{ dx }(t ^{\frac{ 3 }{ 2 }})\] \[=2 *2t  \frac{ 3 }{ 2 }(t ^{\frac{ 1 }{ 2 }})\] \[=4t  \frac{ 3 }{ 2 }(\sqrt{t})\]
 one year ago

JayCT Group TitleBest ResponseYou've already chosen the best response.0
wow thanks very much. i have few other questions, dont know if you would mind helping me?
 one year ago
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