Quantcast

Got Homework?

Connect with other students for help. It's a free community.

  • across
    MIT Grad Student
    Online now
  • laura*
    Helped 1,000 students
    Online now
  • Hero
    College Math Guru
    Online now

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

swin2013 Group Title

Simplify

  • 2 years ago
  • 2 years ago

  • This Question is Closed
  1. swin2013 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    \[\frac{ 2x }{ 4\pi }+ \frac{ 1-x }{ 2 }\]

    • 2 years ago
  2. hartnn Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    is that really \(\pi\) in the denominator of 1st fraction ?

    • 2 years ago
  3. swin2013 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    yes

    • 2 years ago
  4. hartnn Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    now we have to make the denominator common , so we need to multiply and divide by 2\(\pi\) in 2nd fraction to get 4\(\pi\)as common denominator . \(\huge\frac{2x}{4\pi}+\frac{2\pi(1-x)}{4\pi}\) now can u solve further ??

    • 2 years ago
  5. swin2013 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    i got up to \[\frac{ x-pix }{ 2\pi} = 1/2\]

    • 2 years ago
  6. swin2013 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    i mean -1/2

    • 2 years ago
  7. hartnn Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    nopes, \(\huge\frac{2x}{4\pi}+\frac{2\pi(1-x)}{4\pi}=\frac{2x+2\pi(1-x)}{4\pi}=\frac{x+\pi-\pi x}{2\pi}\) u can't simplify it further.

    • 2 years ago
  8. swin2013 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    i forgot one important thing. the equation is equal to zero. and i'm solving for x

    • 2 years ago
  9. hartnn Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    okay, so it will be \(\huge x+\pi-\pi x=0 \implies x(1-\pi)=-\pi \\\huge x=\frac{-\pi}{1-\pi}or\frac{\pi}{\pi-1}\)

    • 2 years ago
  10. swin2013 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    so was my step right so far?

    • 2 years ago
  11. hartnn Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    u got -1/2, but its actually, pi/(pi-1)

    • 2 years ago
  12. swin2013 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    equal to zero? my teacher did the same thing as me.. but i didn't write the last part leading towards the answer.

    • 2 years ago
  13. swin2013 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    i crossed multiply \[\frac{ 4x }{ 8\pi } + \frac{ 4\pi - 4pix }{ 8\pi } = 0\]

    • 2 years ago
  14. swin2013 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    i split the equation up also

    • 2 years ago
  15. hartnn Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    the first term has 'x'

    • 2 years ago
  16. swin2013 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    the i got \[\frac{ x }{ 2\pi } - \frac{ \pi }{ 2\pi } = -1/2 \]

    • 2 years ago
  17. swin2013 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    the \[\frac{ \pi }{ 2 reduces to 1/2 and i brought it over...

    • 2 years ago
  18. hartnn Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    but u cannot cancel pi, the first term had x in it, not pi.

    • 2 years ago
  19. swin2013 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    yes... and i'm solving for it. i haven't found the answer further than that step

    • 2 years ago
  20. swin2013 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    what are you talking about cancel? i didn't cancel anything other than the pis... which was pi/2pi... they're in common? this part i know for sure is right. i don't know how to get after that

    • 2 years ago
  21. hartnn Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    how did u get -1/2 ...and where did your 8 go from denominator ?

    • 2 years ago
  22. swin2013 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    that was a typo. and i reduced \[\frac{ \pi }{ 2\pi } \] to get 1/2 and then i subtracted it on both sides so the equation is equal to -1/2

    • 2 years ago
  23. swin2013 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    i'm basically trying to isolate the x as much as possible

    • 2 years ago
  24. hartnn Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    \(\huge \frac{ 4x }{ 8\pi } + \frac{ 4\pi - 4\pi x }{ 8\pi } = 0\) u had this correct. then u separated denominator u should get, \(\large \frac{x}{2\pi}+\frac{1}{2}-\frac{x}{2}=0\) but this is not the best way to isolate x.

    • 2 years ago
  25. swin2013 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    yea, but it's easier for me to visualize it. instead of clutter i wanted to separate the fractions

    • 2 years ago
  26. hartnn Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    ok, so continuing with separating the fraction, you can cancel all the 2's in the denominator(equivalent to multiplying 2 on both sides.) then shifting +1to other side, u get \(\large x(\frac{1}{\pi}-1)=-1\) which again gives, \(\large x=\frac{-1}{1/\pi-1}=\frac{\pi}{\pi-1}\)

    • 2 years ago
  27. hartnn Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    ok, so continuing with separating the fraction, you can cancel all the 2's in the denominator(equivalent to multiplying 2 on both sides.) then shifting +1to other side, u get \(\large x(\frac{1}{\pi}-1)=-1\) which again gives, \(\large x=\frac{-1}{1/\pi-1}=\frac{\pi}{\pi-1}\)

    • 2 years ago
  28. swin2013 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    so i multiply the top and bottom by 2pi to get rid of it in the denominator?

    • 2 years ago
  29. swin2013 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    where do you get +1?

    • 2 years ago
  30. hartnn Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    yes, u can do that also, that will lead to same answer.

    • 2 years ago
  31. hartnn Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    as i said, i multiplied both sides by 2

    • 2 years ago
  32. hartnn Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    as i said, i multiplied both sides by 2

    • 2 years ago
  33. satellite73 Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    \[\frac{ 2x }{ 4\pi }+ \frac{ 1-x }{ 2 }\] is not an equation. there is nothing to "solve" for you can add however, by finding the lcd is \(4\pi \) and adding

    • 2 years ago
  34. satellite73 Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    you would get \[\frac{2x+2(1-x)}{4\pi}\]

    • 2 years ago
  35. swin2013 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    i got x = \[\frac{ \pi }{ 1-\pi }\]

    • 2 years ago
  36. swin2013 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    - pi / 1-pi = pi / 1+pi

    • 2 years ago
  37. hartnn Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    there must be slight error in minus sign, its pi/(pi-1)

    • 2 years ago
  38. swin2013 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    no, i subtracted 1/2 from both sides and it was -1/2

    • 2 years ago
  39. swin2013 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    then i multiplied both sides by 2pi which made it -pi.

    • 2 years ago
  40. swin2013 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    so i got \[x - pix = -pi\]

    • 2 years ago
  41. hartnn Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    both those steps are correct. u get x(1-pi)=-pi x=-pi/(1-pi) = pi/(pi-1)

    • 2 years ago
  42. swin2013 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    then i factored out the x. \[x(1-\pi) = -\pi \] \[x = \frac{ -\pi }{ 1-\pi } \]

    • 2 years ago
  43. hartnn Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    yes so its -pi/(1-pi) which is same as pi/(pi-1)

    • 2 years ago
  44. swin2013 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    are you sure? if you take out the negative, wouldn't the denominator be 1+ pi?

    • 2 years ago
  45. hartnn Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    nopes it would not be 1+pi. it will be pi-1 -(1-pi) = pi-1 yes, sure.

    • 2 years ago
  46. swin2013 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    ok i see you flipped it around. lol

    • 2 years ago
    • Attachments:

See more questions >>>

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.