Ace school

with brainly

  • Get help from millions of students
  • Learn from experts with step-by-step explanations
  • Level-up by helping others

A community for students.

I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

\[\frac{ 2x }{ 4\pi }+ \frac{ 1-x }{ 2 }\]
is that really \(\pi\) in the denominator of 1st fraction ?
yes

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

now we have to make the denominator common , so we need to multiply and divide by 2\(\pi\) in 2nd fraction to get 4\(\pi\)as common denominator . \(\huge\frac{2x}{4\pi}+\frac{2\pi(1-x)}{4\pi}\) now can u solve further ??
i got up to \[\frac{ x-pix }{ 2\pi} = 1/2\]
i mean -1/2
nopes, \(\huge\frac{2x}{4\pi}+\frac{2\pi(1-x)}{4\pi}=\frac{2x+2\pi(1-x)}{4\pi}=\frac{x+\pi-\pi x}{2\pi}\) u can't simplify it further.
i forgot one important thing. the equation is equal to zero. and i'm solving for x
okay, so it will be \(\huge x+\pi-\pi x=0 \implies x(1-\pi)=-\pi \\\huge x=\frac{-\pi}{1-\pi}or\frac{\pi}{\pi-1}\)
so was my step right so far?
u got -1/2, but its actually, pi/(pi-1)
equal to zero? my teacher did the same thing as me.. but i didn't write the last part leading towards the answer.
i crossed multiply \[\frac{ 4x }{ 8\pi } + \frac{ 4\pi - 4pix }{ 8\pi } = 0\]
i split the equation up also
the first term has 'x'
the i got \[\frac{ x }{ 2\pi } - \frac{ \pi }{ 2\pi } = -1/2 \]
the \[\frac{ \pi }{ 2 reduces to 1/2 and i brought it over...
but u cannot cancel pi, the first term had x in it, not pi.
yes... and i'm solving for it. i haven't found the answer further than that step
what are you talking about cancel? i didn't cancel anything other than the pis... which was pi/2pi... they're in common? this part i know for sure is right. i don't know how to get after that
how did u get -1/2 ...and where did your 8 go from denominator ?
that was a typo. and i reduced \[\frac{ \pi }{ 2\pi } \] to get 1/2 and then i subtracted it on both sides so the equation is equal to -1/2
i'm basically trying to isolate the x as much as possible
\(\huge \frac{ 4x }{ 8\pi } + \frac{ 4\pi - 4\pi x }{ 8\pi } = 0\) u had this correct. then u separated denominator u should get, \(\large \frac{x}{2\pi}+\frac{1}{2}-\frac{x}{2}=0\) but this is not the best way to isolate x.
yea, but it's easier for me to visualize it. instead of clutter i wanted to separate the fractions
ok, so continuing with separating the fraction, you can cancel all the 2's in the denominator(equivalent to multiplying 2 on both sides.) then shifting +1to other side, u get \(\large x(\frac{1}{\pi}-1)=-1\) which again gives, \(\large x=\frac{-1}{1/\pi-1}=\frac{\pi}{\pi-1}\)
ok, so continuing with separating the fraction, you can cancel all the 2's in the denominator(equivalent to multiplying 2 on both sides.) then shifting +1to other side, u get \(\large x(\frac{1}{\pi}-1)=-1\) which again gives, \(\large x=\frac{-1}{1/\pi-1}=\frac{\pi}{\pi-1}\)
so i multiply the top and bottom by 2pi to get rid of it in the denominator?
where do you get +1?
yes, u can do that also, that will lead to same answer.
as i said, i multiplied both sides by 2
as i said, i multiplied both sides by 2
\[\frac{ 2x }{ 4\pi }+ \frac{ 1-x }{ 2 }\] is not an equation. there is nothing to "solve" for you can add however, by finding the lcd is \(4\pi \) and adding
you would get \[\frac{2x+2(1-x)}{4\pi}\]
i got x = \[\frac{ \pi }{ 1-\pi }\]
- pi / 1-pi = pi / 1+pi
there must be slight error in minus sign, its pi/(pi-1)
no, i subtracted 1/2 from both sides and it was -1/2
then i multiplied both sides by 2pi which made it -pi.
so i got \[x - pix = -pi\]
both those steps are correct. u get x(1-pi)=-pi x=-pi/(1-pi) = pi/(pi-1)
then i factored out the x. \[x(1-\pi) = -\pi \] \[x = \frac{ -\pi }{ 1-\pi } \]
yes so its -pi/(1-pi) which is same as pi/(pi-1)
are you sure? if you take out the negative, wouldn't the denominator be 1+ pi?
nopes it would not be 1+pi. it will be pi-1 -(1-pi) = pi-1 yes, sure.
ok i see you flipped it around. lol

Not the answer you are looking for?

Search for more explanations.

Ask your own question