At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this and **thousands** of other questions.

See more answers at brainly.com

Join Brainly to access

this expert answer

SEE EXPERT ANSWER

To see the **expert** answer you'll need to create a **free** account at **Brainly**

this is diff eq'n? sounds like it can be solved via physics.

Well, it can be solved by physics. But it's in my sister's diff eq text book...

@lgbasallote help you took the course don't run D:

Let accleration =a
then, velocity(v)= at+c

now, let total time taken By Alison to complete the race be x then
|dw:1347849846129:dw|

|dw:1347850773445:dw|

Let y be the timetaken by KELVIN to complete the race.^

|dw:1347851115531:dw||dw:1347851153379:dw|

Solving i and ii....... we get:
|dw:1347851218710:dw|

Thus, ALISON won the race by 1/2 seconds

Unfortunately, that's not what my book tells me...

To get speed:
v(t) = s'(t) = Int(k,t) = kt + C

Yessir. Then, we have \(\large s(t)=\frac{1}{2}at^2+v_0t+s(0)\)

So s(t) = (V_i)t+(1/2)at^2

Start velocity is 0 as well.

but, start velocity for the last 1/4 and 1/3 of the race isn't 0.

It doesn't say that...

Nor, of course is starting distance.

oh drag racing

It doesn't say that, but I paraphrased te problem badly. It should be start velocity=0

So, s(t) = (1/2)at^2

yup

geezz that took a while to type out.

Mmm

did you follow?
distance 1 is the first part of the distance, and d2 is the whole distance.

Why are t2's 3 and 4? I mean t is total time, and t1 is elapsed time before that last part?

omg that's a lot of algebras.

kk.

okay, I solved for the time it took Alison to complete the whole thing

actually I did something wrong.... YIKES!

oh no~!

i miss ap cal bc, it was my fave class in hs :/

omg, I just copied the text, and all the subscripts and superscripts were there. :D

coool!

Wait, what was the name of the linear book o.o

Thanks. I'll get a copy somehow.

I think there's a free pdf of it online. Just google it

Found it. Thanks so much man!

np