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3psilon

  • 3 years ago

f(x) = x^3*g(x) , g(-7) = 2 , g'(-7) = -9 . What is f'(7) ?

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  1. completeidiot
    • 3 years ago
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    apply multiplication rule for derivatives i dont remember that actual name for it

  2. love_math
    • 3 years ago
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    use the chain rule to find derivative of f(x)

  3. completeidiot
    • 3 years ago
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    "product rule"

  4. miteshchvm
    • 3 years ago
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    \[f \left( x \right)= x^3 \times g \left( x \right) \] you mean this?

  5. 3psilon
    • 3 years ago
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    yes

  6. miteshchvm
    • 3 years ago
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    \[f \prime \left( x \right)= x^3 \times \left( \frac{ d }{ dx } \right)g \left( x \right) + g \left( x \right) \times \left( \frac{ d }{ dx } \right)x^3\]

  7. miteshchvm
    • 3 years ago
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    \[f \prime \left( x \right)= x^3 \times g \prime \left( x \right) + g \left( x \right) \times 2x^2\]

  8. miteshchvm
    • 3 years ago
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    \[f \prime \left( x \right)= x^3 \times g \prime \left( x \right) + g \left( x \right) \times 3x^2\] this one

  9. miteshchvm
    • 3 years ago
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    now to find \[f \prime \left( 7 \right) =7^3 \times \left( -9 \right) + 2 \times \left( 3 \times7^2 \right)\]

  10. love_math
    • 3 years ago
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    what is g(7), only know g(-7)

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