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SugarRainbow
Group Title
how would you find ^3square root of 38
if you know how I would put that on a calculator that's fine too
 one year ago
 one year ago
SugarRainbow Group Title
how would you find ^3square root of 38 if you know how I would put that on a calculator that's fine too
 one year ago
 one year ago

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miteshchvm Group TitleBest ResponseYou've already chosen the best response.0
do you have a scienrific calculator?
 one year ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.1
dw:1347856598297:dw
 one year ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.1
Type it on calculator
 one year ago

SugarRainbow Group TitleBest ResponseYou've already chosen the best response.0
okay please hold
 one year ago

SugarRainbow Group TitleBest ResponseYou've already chosen the best response.0
i gots 3.36
 one year ago

SugarRainbow Group TitleBest ResponseYou've already chosen the best response.0
just so everyone absolutely knows the problem looks like this dw:1347856966969:dw
 one year ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.1
Yes thats it
 one year ago

SugarRainbow Group TitleBest ResponseYou've already chosen the best response.0
o kay now how would you find the value of the expression : if sin beta=0.45, find cos(pi/2beta)
 one year ago

miteshchvm Group TitleBest ResponseYou've already chosen the best response.0
its the same
 one year ago

SugarRainbow Group TitleBest ResponseYou've already chosen the best response.0
okay then i did it right, what bout if tan(pi/2beta)=5.32, find cot beta
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
tan(pi/2beta)= cot beta = 5.32
 one year ago

SugarRainbow Group TitleBest ResponseYou've already chosen the best response.0
okay cool then I think i got it so if sin (betapi/2)=0.73, to find cosbeta i would do cos(sin^1pi/2) right? or cos^1(sin^1pi/2)
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
remember these identities: \(sin(\pi/2\beta)=cos\beta \\ tan(\pi/2\beta)=cot\beta \\ cos(\pi/2\beta)=sin\beta \) when the ratio has angle \(\pi/2  \beta\) , it becomes coratio.
 one year ago

SugarRainbow Group TitleBest ResponseYou've already chosen the best response.0
so is it the same if its betapi/2 instead of pi/2beta?
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
no, its only for pi/2beta for betapi/2, u write it as (pi/2beta) and use sin(x)=sin x cos(x)=cos x tan(x)=tan x
 one year ago

SugarRainbow Group TitleBest ResponseYou've already chosen the best response.0
okay so to do if sin (betapi/2)=0.73, find cosbeta it would be cos(pi/2sin^1(0.73)?
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
there is no need to do \(sin^{1}\)here. \(sin(\beta\pi/2)=sin((\pi/2\beta))=sin(\pi/2\beta)=cos\beta\)
 one year ago

SugarRainbow Group TitleBest ResponseYou've already chosen the best response.0
so then how would i do the problem?
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
so cos beta = sin (betapi/2)= 0.73
 one year ago

SugarRainbow Group TitleBest ResponseYou've already chosen the best response.0
oh well IDK how i did it but I got that answer too. okay so last one of these is if cot(beta)=7.89, find tan( betapi/2) would it kinda be like the previous one?
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
yes. use tan(betapi/2) = tan((pi/2beta))=??
 one year ago

SugarRainbow Group TitleBest ResponseYou've already chosen the best response.0
please hold
 one year ago

SugarRainbow Group TitleBest ResponseYou've already chosen the best response.0
0.03? wait I think i did it wrong let me try again
 one year ago

SugarRainbow Group TitleBest ResponseYou've already chosen the best response.0
um okay one last try
 one year ago

SugarRainbow Group TitleBest ResponseYou've already chosen the best response.0
1.20?
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
ok, from where are u getting those numbers ?? tan(betapi/2) = tan((pi/2beta))=tan(pi/2beta)=cot beta and cot(beta)=cot beta also so tan(betapi/2) = cot(beta) =7.89 see whether u understand this ?
 one year ago

SugarRainbow Group TitleBest ResponseYou've already chosen the best response.0
well idk what i put for beta i tried it as just 7.89 and cot(7.89) here i'll try it again
 one year ago

SugarRainbow Group TitleBest ResponseYou've already chosen the best response.0
well i understand how it works but idk how to put it into my calc to where i get that answer
 one year ago
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