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anonymous
 3 years ago
how would you find ^3square root of 38
if you know how I would put that on a calculator that's fine too
anonymous
 3 years ago
how would you find ^3square root of 38 if you know how I would put that on a calculator that's fine too

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0do you have a scienrific calculator?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1347856598297:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Type it on calculator

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0just so everyone absolutely knows the problem looks like this dw:1347856966969:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0o kay now how would you find the value of the expression : if sin beta=0.45, find cos(pi/2beta)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0okay then i did it right, what bout if tan(pi/2beta)=5.32, find cot beta

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1tan(pi/2beta)= cot beta = 5.32

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0okay cool then I think i got it so if sin (betapi/2)=0.73, to find cosbeta i would do cos(sin^1pi/2) right? or cos^1(sin^1pi/2)

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1remember these identities: \(sin(\pi/2\beta)=cos\beta \\ tan(\pi/2\beta)=cot\beta \\ cos(\pi/2\beta)=sin\beta \) when the ratio has angle \(\pi/2  \beta\) , it becomes coratio.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so is it the same if its betapi/2 instead of pi/2beta?

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1no, its only for pi/2beta for betapi/2, u write it as (pi/2beta) and use sin(x)=sin x cos(x)=cos x tan(x)=tan x

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0okay so to do if sin (betapi/2)=0.73, find cosbeta it would be cos(pi/2sin^1(0.73)?

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1there is no need to do \(sin^{1}\)here. \(sin(\beta\pi/2)=sin((\pi/2\beta))=sin(\pi/2\beta)=cos\beta\)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so then how would i do the problem?

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1so cos beta = sin (betapi/2)= 0.73

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0oh well IDK how i did it but I got that answer too. okay so last one of these is if cot(beta)=7.89, find tan( betapi/2) would it kinda be like the previous one?

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1yes. use tan(betapi/2) = tan((pi/2beta))=??

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.00.03? wait I think i did it wrong let me try again

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1ok, from where are u getting those numbers ?? tan(betapi/2) = tan((pi/2beta))=tan(pi/2beta)=cot beta and cot(beta)=cot beta also so tan(betapi/2) = cot(beta) =7.89 see whether u understand this ?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0well idk what i put for beta i tried it as just 7.89 and cot(7.89) here i'll try it again

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0well i understand how it works but idk how to put it into my calc to where i get that answer
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