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SugarRainbow
Group Title
how would you find ^3square root of 38
if you know how I would put that on a calculator that's fine too
 2 years ago
 2 years ago
SugarRainbow Group Title
how would you find ^3square root of 38 if you know how I would put that on a calculator that's fine too
 2 years ago
 2 years ago

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miteshchvm Group TitleBest ResponseYou've already chosen the best response.0
do you have a scienrific calculator?
 2 years ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.1
dw:1347856598297:dw
 2 years ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.1
Type it on calculator
 2 years ago

SugarRainbow Group TitleBest ResponseYou've already chosen the best response.0
okay please hold
 2 years ago

SugarRainbow Group TitleBest ResponseYou've already chosen the best response.0
i gots 3.36
 2 years ago

SugarRainbow Group TitleBest ResponseYou've already chosen the best response.0
just so everyone absolutely knows the problem looks like this dw:1347856966969:dw
 2 years ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.1
Yes thats it
 2 years ago

SugarRainbow Group TitleBest ResponseYou've already chosen the best response.0
o kay now how would you find the value of the expression : if sin beta=0.45, find cos(pi/2beta)
 2 years ago

miteshchvm Group TitleBest ResponseYou've already chosen the best response.0
its the same
 2 years ago

SugarRainbow Group TitleBest ResponseYou've already chosen the best response.0
okay then i did it right, what bout if tan(pi/2beta)=5.32, find cot beta
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
tan(pi/2beta)= cot beta = 5.32
 2 years ago

SugarRainbow Group TitleBest ResponseYou've already chosen the best response.0
okay cool then I think i got it so if sin (betapi/2)=0.73, to find cosbeta i would do cos(sin^1pi/2) right? or cos^1(sin^1pi/2)
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
remember these identities: \(sin(\pi/2\beta)=cos\beta \\ tan(\pi/2\beta)=cot\beta \\ cos(\pi/2\beta)=sin\beta \) when the ratio has angle \(\pi/2  \beta\) , it becomes coratio.
 2 years ago

SugarRainbow Group TitleBest ResponseYou've already chosen the best response.0
so is it the same if its betapi/2 instead of pi/2beta?
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
no, its only for pi/2beta for betapi/2, u write it as (pi/2beta) and use sin(x)=sin x cos(x)=cos x tan(x)=tan x
 2 years ago

SugarRainbow Group TitleBest ResponseYou've already chosen the best response.0
okay so to do if sin (betapi/2)=0.73, find cosbeta it would be cos(pi/2sin^1(0.73)?
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
there is no need to do \(sin^{1}\)here. \(sin(\beta\pi/2)=sin((\pi/2\beta))=sin(\pi/2\beta)=cos\beta\)
 2 years ago

SugarRainbow Group TitleBest ResponseYou've already chosen the best response.0
so then how would i do the problem?
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
so cos beta = sin (betapi/2)= 0.73
 2 years ago

SugarRainbow Group TitleBest ResponseYou've already chosen the best response.0
oh well IDK how i did it but I got that answer too. okay so last one of these is if cot(beta)=7.89, find tan( betapi/2) would it kinda be like the previous one?
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
yes. use tan(betapi/2) = tan((pi/2beta))=??
 2 years ago

SugarRainbow Group TitleBest ResponseYou've already chosen the best response.0
please hold
 2 years ago

SugarRainbow Group TitleBest ResponseYou've already chosen the best response.0
0.03? wait I think i did it wrong let me try again
 2 years ago

SugarRainbow Group TitleBest ResponseYou've already chosen the best response.0
um okay one last try
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
ok, from where are u getting those numbers ?? tan(betapi/2) = tan((pi/2beta))=tan(pi/2beta)=cot beta and cot(beta)=cot beta also so tan(betapi/2) = cot(beta) =7.89 see whether u understand this ?
 2 years ago

SugarRainbow Group TitleBest ResponseYou've already chosen the best response.0
well idk what i put for beta i tried it as just 7.89 and cot(7.89) here i'll try it again
 2 years ago

SugarRainbow Group TitleBest ResponseYou've already chosen the best response.0
well i understand how it works but idk how to put it into my calc to where i get that answer
 2 years ago
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