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jpjones

  • 3 years ago

find f'(x) if f(x) = ln(sinx)

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  1. love_math
    • 3 years ago
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    derivative of sinx divided by sinx

  2. anonymous
    • 3 years ago
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    \[\frac{d}{dx}[\ln(f(x))]=\frac{f'(x)}{f(x)}\] via the chain rule

  3. anonymous
    • 3 years ago
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    oops

  4. love_math
    • 3 years ago
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    cotx

  5. franciscanmonk
    • 3 years ago
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    f(x) = ln(sinx) y' = (1/sinx)(cosx) y' = cosx/sinx y' = cotx

  6. sauravshakya
    • 3 years ago
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    f'(x)=d(lnsinx)/dx = {d(ln sinx) /dsinx} * {dsinx /dx} ={1/sinx} *{cosx} =cosx/sinx =cotx

  7. sauravshakya
    • 3 years ago
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    got it?

  8. lgbasallote
    • 3 years ago
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    oops? @satellite73

  9. jpjones
    • 3 years ago
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    why cot x and not tan x

  10. anonymous
    • 3 years ago
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    there was an erroneous tangent floating around, it is gone

  11. anonymous
    • 3 years ago
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    oh look, it came back!!

  12. sauravshakya
    • 3 years ago
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    U can write it interms of tan x too

  13. sauravshakya
    • 3 years ago
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    BUT: f'(x)= 1/tan x

  14. jpjones
    • 3 years ago
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    thanks

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