jpjones
find f'(x) if f(x) = ln(sinx)



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love_math
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derivative of sinx divided by sinx

anonymous
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\[\frac{d}{dx}[\ln(f(x))]=\frac{f'(x)}{f(x)}\] via the chain rule

anonymous
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oops

love_math
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cotx

franciscanmonk
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f(x) = ln(sinx)
y' = (1/sinx)(cosx)
y' = cosx/sinx
y' = cotx

sauravshakya
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f'(x)=d(lnsinx)/dx
= {d(ln sinx) /dsinx} * {dsinx /dx}
={1/sinx} *{cosx}
=cosx/sinx
=cotx

sauravshakya
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got it?

lgbasallote
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oops? @satellite73

jpjones
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why cot x and not tan x

anonymous
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there was an erroneous tangent floating around,
it is gone

anonymous
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oh look, it came back!!

sauravshakya
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U can write it interms of tan x too

sauravshakya
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BUT:
f'(x)= 1/tan x

jpjones
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thanks