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qpHalcy0n Group TitleBest ResponseYou've already chosen the best response.1
Remember tangent is just sin(x)/cos(x)
 one year ago

SugarRainbow Group TitleBest ResponseYou've already chosen the best response.0
so its cos x (sin x / cos x) ?
 one year ago

qpHalcy0n Group TitleBest ResponseYou've already chosen the best response.1
Correct, now what happens when you go ahead and multiply the cosine?
 one year ago

SugarRainbow Group TitleBest ResponseYou've already chosen the best response.0
sin x
 one year ago

qpHalcy0n Group TitleBest ResponseYou've already chosen the best response.1
That's it. The cosines cancel.
 one year ago

SugarRainbow Group TitleBest ResponseYou've already chosen the best response.0
okay cool what bout sec y sin (pi/2y)? IDK how to do this at all
 one year ago

qpHalcy0n Group TitleBest ResponseYou've already chosen the best response.1
\[\sec(y)\sin(\frac{\pi}{2y})\] ??
 one year ago

SugarRainbow Group TitleBest ResponseYou've already chosen the best response.0
but isnt it like pi/2  y not pi/ 2y
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
sin(pi/2y)=cos y sec y= 1/cos y
 one year ago

qpHalcy0n Group TitleBest ResponseYou've already chosen the best response.1
Ok, so rewrite secant as 1/cos
 one year ago

qpHalcy0n Group TitleBest ResponseYou've already chosen the best response.1
Then you can use a fancy pants trig identity.
 one year ago

SugarRainbow Group TitleBest ResponseYou've already chosen the best response.0
cos y 1/cos y
 one year ago

qpHalcy0n Group TitleBest ResponseYou've already chosen the best response.1
dw:1347861835303:dw Right?
 one year ago

SugarRainbow Group TitleBest ResponseYou've already chosen the best response.0
i think so i was kinda looking at what hartnns post too so couldn't you do it likedw:1347861948541:dw
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
sec y =1/ cos y is in numerator, so it would be :dw:1347862109049:dw
 one year ago

qpHalcy0n Group TitleBest ResponseYou've already chosen the best response.1
No, well what you would have is a multiplication, the cosines would cancel.
 one year ago

SugarRainbow Group TitleBest ResponseYou've already chosen the best response.0
oh hey you know how tan x= sinx/ cos x well what are the rest of those cuz it might help me understand better like how we getting cos y when its sin y
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
ok, so u want all trignometric formulas ? for converting one ratio to other ?
 one year ago

SugarRainbow Group TitleBest ResponseYou've already chosen the best response.0
yes please
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
i will list some : \(\huge sin x =1/cosec x \implies cosec x=1/sin x \\\huge cos x = 1/sec x \implies secx=1/cos x \\\huge tan x=1/cot x \implies cot x =1/tanx \\\huge tan x=sin x/cos x \\\huge cot x=cos x/sinx \\ \huge sin^2x+cos^2x=1 \\\huge sec^2x=1+tan^2x\\\huge cosec^2x=1+cot^2x\)
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
if u want sin x when cos x is given or if u want cos x when sin x is given, u use: \(sin^2x+cos^2x=1\)
 one year ago

SugarRainbow Group TitleBest ResponseYou've already chosen the best response.0
so if its 1+tan^2x/csc^2x that would simplify to sec^2x/csc^2
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
yes. or is it ? \(\large1+\frac{tan^2x}{cosec^2x}\quad?\)
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
if it is \(\large\frac{1+tan^2x}{cosec^2x}=\frac{sec^2x}{cosec^2x}=\frac{sin^2x}{cos^2x}=tan^2x\)
 one year ago

SugarRainbow Group TitleBest ResponseYou've already chosen the best response.0
but you put that cos^2x=1+cot^2x
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
no the last one is cosec^2 x =1+cot^2 x not cos^2x=1+cot^2x
 one year ago

SugarRainbow Group TitleBest ResponseYou've already chosen the best response.0
oh yeah huh cosec is csc not cos i forgot for a minute lol
 one year ago

SugarRainbow Group TitleBest ResponseYou've already chosen the best response.0
so is it 1+ tan^2x/csc^2x or sec^2x/csc^2 and why
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
what exactly is your question ? is this : (1+ tan^2x)/csc^2x
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
(1+ tan^2x)=sec^2 x from the formula i gave u.
 one year ago

SugarRainbow Group TitleBest ResponseYou've already chosen the best response.0
no i saying is it my answer or yours and why (idk how to put it on my computer like you did so that was the best i could do)
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
to tell u what is your answer, i need to know your exact question, that is why i asked whether it is: (1+ tan^2x)/csc^2x
 one year ago

SugarRainbow Group TitleBest ResponseYou've already chosen the best response.0
oh yeah it's that and i need to simplify it
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
ok,for that i have shown u the steps, tell me which step, u didn't understand: \(\large\frac{1+tan^2x}{cosec^2x}=\frac{sec^2x}{cosec^2x}=\frac{sin^2x}{cos^2x}=tan^2x\)
 one year ago

SugarRainbow Group TitleBest ResponseYou've already chosen the best response.0
oh i get it now earlier you put it wierd so i didn't get it
 one year ago

SugarRainbow Group TitleBest ResponseYou've already chosen the best response.0
okay now this one is cot x tan x so it would be (cosx/sinx)(sinx/cosx) correct?
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
yes, or u could use cot x = 1/ tanx and u get tan x / tan x =1
 one year ago

SugarRainbow Group TitleBest ResponseYou've already chosen the best response.0
wait because i have two of each would thay cancel out?
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
yes, they would. sin x cos x / sin x cos x =1
 one year ago

SugarRainbow Group TitleBest ResponseYou've already chosen the best response.0
oh okay just checking
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
dw:1347864987907:dw
 one year ago

SugarRainbow Group TitleBest ResponseYou've already chosen the best response.0
how bout cot u sin u would that simplify to (cosu/sinu)sin u= cos u?
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
thats absolutely correct! u are improving :)
 one year ago

SugarRainbow Group TitleBest ResponseYou've already chosen the best response.0
hooray improvement!
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
what next ?
 one year ago

SugarRainbow Group TitleBest ResponseYou've already chosen the best response.0
1cos^2 beta/sin beta and that would simplify to ooh okay i got nothin for this one :(
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
is the numerator (1cos^2 beta ) ??
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
from sin^2 beta +cos^2 beta =1 u have 1cos^2 beta = sin^2 beta so u have : \(\large \frac{sin^2 \beta}{sin \beta}=\frac{sin \beta.sin\beta}{sin \beta}=?\)
 one year ago

SugarRainbow Group TitleBest ResponseYou've already chosen the best response.0
sin beta?
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
yup, but did u get all steps ?
 one year ago

SugarRainbow Group TitleBest ResponseYou've already chosen the best response.0
yeah so is that another function 1cos^2 beta = sin^2 beta
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
see the list i have given. it has sin^2 x + cos^2 x =1 isn't it ? from here i got 1cos^2 x = sin^2 x clear ?
 one year ago

SugarRainbow Group TitleBest ResponseYou've already chosen the best response.0
oh so you just went backwards?
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
whenever u see sin^2 x or cos^2 x try to use that formula for simplification.
 one year ago

SugarRainbow Group TitleBest ResponseYou've already chosen the best response.0
okay now i have cos x cos^3 x
 one year ago

SugarRainbow Group TitleBest ResponseYou've already chosen the best response.0
like would that be cosx (cosx)(cosx)/cosx?
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
nopes. take cos x common from both the terms, what do u get ?
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
cosx (cosx)(cosx)(cosx)
 one year ago

SugarRainbow Group TitleBest ResponseYou've already chosen the best response.0
so you get 1
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
no! after taking cos x common, u get cos x (1(cos x)(cos x) ) =cos x (1 cos^2 x) and u already know what is (1 cos^2 x)
 one year ago

SugarRainbow Group TitleBest ResponseYou've already chosen the best response.0
sin^2x
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
yes! so your final answer will be cos x sin^2x but did u get all the steps ?
 one year ago

SugarRainbow Group TitleBest ResponseYou've already chosen the best response.0
yeah because you have coxx(cosx)(cosx)(cosx) =cosx1(cosx)=1cos^2x=sin^2x
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
i will draw it :dw:1347866550463:dw
 one year ago

SugarRainbow Group TitleBest ResponseYou've already chosen the best response.0
oh okay then now my last question is sin^2 u + tan^2 u +cos^2 u/sec u
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
is this entire thing (sin^2 u + tan^2 u +cos^2 u) in the numerator ?
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
again using sin^2 x +cos^2 x =1, u have numerator as (1+tan^2 x) got this ? and (1+tan^2 x) = sec^2 x.....see formula list. so u have now sec^2x/sec x = ??
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
replace all of my 'x' with 'u'
 one year ago

SugarRainbow Group TitleBest ResponseYou've already chosen the best response.0
oh yeah so now you have sec x!
 one year ago

SugarRainbow Group TitleBest ResponseYou've already chosen the best response.0
oh yeah lol thanks for your help i going to sleep now so goodnight^^
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
a very good night to u and have sweet dreams :)
 one year ago
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