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akhil009

  • 2 years ago

find the reaction at hinge point ?

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  1. akhil009
    • 2 years ago
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    |dw:1347883884640:dw|

  2. akhil009
    • 2 years ago
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    @Vincent-Lyon.Fr

  3. akhil009
    • 2 years ago
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    there wasn't any thing written about time and impulse so i guess its simply the force acting normally on bar

  4. Vincent-Lyon.Fr
    • 2 years ago
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    If the hinge is unlocked and friction-free, the rod will not stay vertical and the sketch has to be redrawn. Then the hinge will exert a single force to the left and up. If the hinge is locked, the rod will stay vertical and the action by the hinge will be the association of a force (to compensate for the weight and the push) and a torque (to compensate the moment exerted by the push)

  5. akhil009
    • 2 years ago
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    at t=0 are static equilibrium conditions are valid ?

  6. akhil009
    • 2 years ago
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    i know you have applied dynamics equation I am just asking for t=0 when motion hasn't started can we apply static eq. and btw the answer for this Q is P/3 and I am still clueless about ans..

  7. Vincent-Lyon.Fr
    • 2 years ago
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    Ok, I see now what the problem is. Will have another try.

  8. Vincent-Lyon.Fr
    • 2 years ago
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    demitris's solution is correct. Rx will be zero. In order to have |Rx| = P/3 you need to exert the push at distance d from the hinge such as: d = 4L/9 then Rx is to the right or d = 8L/9 then Rx is to the left

  9. akhil009
    • 2 years ago
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    |dw:1348679543385:dw| is there any way so that i can find theta suppose at theta rod is stable now equllibrium equations are valid so by applying moment and force equations

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