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akhil009
 2 years ago
Best ResponseYou've already chosen the best response.0there wasn't any thing written about time and impulse so i guess its simply the force acting normally on bar

VincentLyon.Fr
 2 years ago
Best ResponseYou've already chosen the best response.0If the hinge is unlocked and frictionfree, the rod will not stay vertical and the sketch has to be redrawn. Then the hinge will exert a single force to the left and up. If the hinge is locked, the rod will stay vertical and the action by the hinge will be the association of a force (to compensate for the weight and the push) and a torque (to compensate the moment exerted by the push)

akhil009
 2 years ago
Best ResponseYou've already chosen the best response.0at t=0 are static equilibrium conditions are valid ?

akhil009
 2 years ago
Best ResponseYou've already chosen the best response.0i know you have applied dynamics equation I am just asking for t=0 when motion hasn't started can we apply static eq. and btw the answer for this Q is P/3 and I am still clueless about ans..

VincentLyon.Fr
 2 years ago
Best ResponseYou've already chosen the best response.0Ok, I see now what the problem is. Will have another try.

VincentLyon.Fr
 2 years ago
Best ResponseYou've already chosen the best response.0demitris's solution is correct. Rx will be zero. In order to have Rx = P/3 you need to exert the push at distance d from the hinge such as: d = 4L/9 then Rx is to the right or d = 8L/9 then Rx is to the left

akhil009
 2 years ago
Best ResponseYou've already chosen the best response.0dw:1348679543385:dw is there any way so that i can find theta suppose at theta rod is stable now equllibrium equations are valid so by applying moment and force equations
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