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akhil009 Group TitleBest ResponseYou've already chosen the best response.0
dw:1347883884640:dw
 one year ago

akhil009 Group TitleBest ResponseYou've already chosen the best response.0
@VincentLyon.Fr
 one year ago

akhil009 Group TitleBest ResponseYou've already chosen the best response.0
there wasn't any thing written about time and impulse so i guess its simply the force acting normally on bar
 one year ago

VincentLyon.Fr Group TitleBest ResponseYou've already chosen the best response.0
If the hinge is unlocked and frictionfree, the rod will not stay vertical and the sketch has to be redrawn. Then the hinge will exert a single force to the left and up. If the hinge is locked, the rod will stay vertical and the action by the hinge will be the association of a force (to compensate for the weight and the push) and a torque (to compensate the moment exerted by the push)
 one year ago

akhil009 Group TitleBest ResponseYou've already chosen the best response.0
at t=0 are static equilibrium conditions are valid ?
 one year ago

akhil009 Group TitleBest ResponseYou've already chosen the best response.0
i know you have applied dynamics equation I am just asking for t=0 when motion hasn't started can we apply static eq. and btw the answer for this Q is P/3 and I am still clueless about ans..
 one year ago

VincentLyon.Fr Group TitleBest ResponseYou've already chosen the best response.0
Ok, I see now what the problem is. Will have another try.
 one year ago

VincentLyon.Fr Group TitleBest ResponseYou've already chosen the best response.0
demitris's solution is correct. Rx will be zero. In order to have Rx = P/3 you need to exert the push at distance d from the hinge such as: d = 4L/9 then Rx is to the right or d = 8L/9 then Rx is to the left
 one year ago

akhil009 Group TitleBest ResponseYou've already chosen the best response.0
dw:1348679543385:dw is there any way so that i can find theta suppose at theta rod is stable now equllibrium equations are valid so by applying moment and force equations
 one year ago
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