Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing

This Question is Closed

akhil009 Group TitleBest ResponseYou've already chosen the best response.0
dw:1347883884640:dw
 2 years ago

akhil009 Group TitleBest ResponseYou've already chosen the best response.0
@VincentLyon.Fr
 2 years ago

akhil009 Group TitleBest ResponseYou've already chosen the best response.0
there wasn't any thing written about time and impulse so i guess its simply the force acting normally on bar
 2 years ago

VincentLyon.Fr Group TitleBest ResponseYou've already chosen the best response.0
If the hinge is unlocked and frictionfree, the rod will not stay vertical and the sketch has to be redrawn. Then the hinge will exert a single force to the left and up. If the hinge is locked, the rod will stay vertical and the action by the hinge will be the association of a force (to compensate for the weight and the push) and a torque (to compensate the moment exerted by the push)
 2 years ago

akhil009 Group TitleBest ResponseYou've already chosen the best response.0
at t=0 are static equilibrium conditions are valid ?
 2 years ago

akhil009 Group TitleBest ResponseYou've already chosen the best response.0
i know you have applied dynamics equation I am just asking for t=0 when motion hasn't started can we apply static eq. and btw the answer for this Q is P/3 and I am still clueless about ans..
 2 years ago

VincentLyon.Fr Group TitleBest ResponseYou've already chosen the best response.0
Ok, I see now what the problem is. Will have another try.
 2 years ago

VincentLyon.Fr Group TitleBest ResponseYou've already chosen the best response.0
demitris's solution is correct. Rx will be zero. In order to have Rx = P/3 you need to exert the push at distance d from the hinge such as: d = 4L/9 then Rx is to the right or d = 8L/9 then Rx is to the left
 2 years ago

akhil009 Group TitleBest ResponseYou've already chosen the best response.0
dw:1348679543385:dw is there any way so that i can find theta suppose at theta rod is stable now equllibrium equations are valid so by applying moment and force equations
 2 years ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.