anonymous
  • anonymous
Prove that the opposite angles of a parallelogram are congruent.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
anonymous
  • anonymous
Can anyone help?
mayankdevnani
  • mayankdevnani
Well, that's a property of parallelograms.

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mayankdevnani
  • mayankdevnani
But if you must prove it, I say you draw a diagonal from one angle to the opposite one, and then prove that the two triangles formed are congruent, since their three sides have the same length.
mayankdevnani
  • mayankdevnani
After that, just prove that the opposite angles are congruent because correspondent angles on congruent triangles are congruent.. @BIGDOG96
jiteshmeghwal9
  • jiteshmeghwal9
|dw:1347976457702:dw|
jiteshmeghwal9
  • jiteshmeghwal9
so here through this congruency it is proved that opposite angles of a parallelogram are always equal.
anonymous
  • anonymous
Thanks
jiteshmeghwal9
  • jiteshmeghwal9
yw :)
mayankdevnani
  • mayankdevnani
welcome...
anonymous
  • anonymous
I get it better with the pic
anonymous
  • anonymous
Is there anyway you could write out the steps, they kinda got chopped off. @jiteshmeghwal9
jiteshmeghwal9
  • jiteshmeghwal9
yes!
jiteshmeghwal9
  • jiteshmeghwal9
write my first & second replies
jiteshmeghwal9
  • jiteshmeghwal9
cleanly,in ur note-book
jiteshmeghwal9
  • jiteshmeghwal9
they are the steps :)
anonymous
  • anonymous
Is any of that missing?
anonymous
  • anonymous
Is this right? First draw two bisectors in the parallelogram. So, here is a parallelogram namely ABCD. angle 5 = angle 4 alternate interior angles congruency. 1 - 2 - angle 6 = angle 3 alternate interior angles congruency. 3 -angle 1 = angle 8 alternate interior angle congruency. 4 - angle 2 = angle 7 alternate interior angle congruency.
jiteshmeghwal9
  • jiteshmeghwal9
yes!
anonymous
  • anonymous
Okay thanks. Can you help with another one?
jiteshmeghwal9
  • jiteshmeghwal9
Hmm! if the question is not same then i will help you because i have cleared ur concept :)
jiteshmeghwal9
  • jiteshmeghwal9
in this type of question
anonymous
  • anonymous
Will you check my work?
jiteshmeghwal9
  • jiteshmeghwal9
ok!

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