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sasogeek

  • 3 years ago

if i'm supposed to write a given log as a single logarithm, would this be right given \(\large (x+6)log_4 3\) ans. \(\large log_4 3^x + log_4 3^6 \) ?

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  1. across
    • 3 years ago
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    There's one last step.

  2. sasogeek
    • 3 years ago
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    \(\large xlog_4 3+6log_4 3 \) ?

  3. amistre64
    • 3 years ago
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    a shorter route may be:\[n~log(a)=log(a^n)\]

  4. across
    • 3 years ago
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    Recall that \(\log a+\log b=\log ab\).

  5. mathslover
    • 3 years ago
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    |dw:1347889346978:dw|

  6. jiteshmeghwal9
    • 3 years ago
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    \[\Huge{\color{red}{Remember :}}\]\[\Huge{\color{green}{n \log_{a}{b} \color{purple}{\implies} \color{blue}{\log_{a}{b^n}}}}\]

  7. jiteshmeghwal9
    • 3 years ago
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    & @mathslover is right :)

  8. sasogeek
    • 3 years ago
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    ok thanks :)

  9. mathslover
    • 3 years ago
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    You're most welcome "sir"

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