sasogeek
if i'm supposed to write a given log as a single logarithm, would this be right given
\(\large (x+6)log_4 3\)
ans. \(\large log_4 3^x + log_4 3^6 \) ?



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across
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There's one last step.

sasogeek
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\(\large xlog_4 3+6log_4 3 \) ?

amistre64
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a shorter route may be:\[n~log(a)=log(a^n)\]

across
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Recall that \(\log a+\log b=\log ab\).

mathslover
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dw:1347889346978:dw

jiteshmeghwal9
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\[\Huge{\color{red}{Remember :}}\]\[\Huge{\color{green}{n \log_{a}{b} \color{purple}{\implies} \color{blue}{\log_{a}{b^n}}}}\]

jiteshmeghwal9
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& @mathslover is right :)

sasogeek
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ok thanks :)

mathslover
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You're most welcome "sir"