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jiteshmeghwal9 Group TitleBest ResponseYou've already chosen the best response.2
by squaring both sides\[2x1=9\]
 one year ago

pratu043 Group TitleBest ResponseYou've already chosen the best response.1
\[\sqrt{2x  1} = 3\] Square on both sides. \[2x  1 = 9\] Quite simple now, can you do it?
 one year ago

jiteshmeghwal9 Group TitleBest ResponseYou've already chosen the best response.2
solve for 'x' from here
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.2
don't even start this problem \(\sqrt{2x1}\) is positive, whereas \(3\) is negative, so there is no solution
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.2
don't square both sides, don't do anything at all a positive number cannot equal a negative one say "no solution" and be done
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.2
which is good example of making sure you think before you apply some method to a problem
 one year ago

math0101 Group TitleBest ResponseYou've already chosen the best response.0
Hmm... the sqrt(9) isn't 3, but I don't see how that disallows 3^2
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.2
i am assuming you are looking for a real value for \(x\) and not two complex numbers whose square is \(3\)
 one year ago

jiteshmeghwal9 Group TitleBest ResponseYou've already chosen the best response.2
but @satellite73 sir this gives the condition of the question but he needs to solve for 'x'
 one year ago

pratu043 Group TitleBest ResponseYou've already chosen the best response.1
I didn't think from that point of view.
 one year ago

pratu043 Group TitleBest ResponseYou've already chosen the best response.1
That was a good point.
 one year ago

math0101 Group TitleBest ResponseYou've already chosen the best response.0
Allright, I think I'm getting it. Thanks for all the help. :)
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.2
if so (and i really really doubt it) then this method \[2x1=9\] \[2x=10\] \[x=5\] will certainly not work, and the check is easy \[\sqrt{2\times 51}=\sqrt{9}=3\neq 3\]
 one year ago

jiteshmeghwal9 Group TitleBest ResponseYou've already chosen the best response.2
hmmmm......
 one year ago

jiteshmeghwal9 Group TitleBest ResponseYou've already chosen the best response.2
u r right sir :) sorry!
 one year ago

math0101 Group TitleBest ResponseYou've already chosen the best response.0
Excellent answer, satellite73!
 one year ago

jiteshmeghwal9 Group TitleBest ResponseYou've already chosen the best response.2
@math0101 for steps u can first solve it & prove this wrong or other answer is as @satellite73 sir's answer :)
 one year ago
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