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jiteshmeghwal9 Group TitleBest ResponseYou've already chosen the best response.2
by squaring both sides\[2x1=9\]
 2 years ago

pratu043 Group TitleBest ResponseYou've already chosen the best response.1
\[\sqrt{2x  1} = 3\] Square on both sides. \[2x  1 = 9\] Quite simple now, can you do it?
 2 years ago

jiteshmeghwal9 Group TitleBest ResponseYou've already chosen the best response.2
solve for 'x' from here
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.2
don't even start this problem \(\sqrt{2x1}\) is positive, whereas \(3\) is negative, so there is no solution
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.2
don't square both sides, don't do anything at all a positive number cannot equal a negative one say "no solution" and be done
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.2
which is good example of making sure you think before you apply some method to a problem
 2 years ago

math0101 Group TitleBest ResponseYou've already chosen the best response.0
Hmm... the sqrt(9) isn't 3, but I don't see how that disallows 3^2
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.2
i am assuming you are looking for a real value for \(x\) and not two complex numbers whose square is \(3\)
 2 years ago

jiteshmeghwal9 Group TitleBest ResponseYou've already chosen the best response.2
but @satellite73 sir this gives the condition of the question but he needs to solve for 'x'
 2 years ago

pratu043 Group TitleBest ResponseYou've already chosen the best response.1
I didn't think from that point of view.
 2 years ago

pratu043 Group TitleBest ResponseYou've already chosen the best response.1
That was a good point.
 2 years ago

math0101 Group TitleBest ResponseYou've already chosen the best response.0
Allright, I think I'm getting it. Thanks for all the help. :)
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.2
if so (and i really really doubt it) then this method \[2x1=9\] \[2x=10\] \[x=5\] will certainly not work, and the check is easy \[\sqrt{2\times 51}=\sqrt{9}=3\neq 3\]
 2 years ago

jiteshmeghwal9 Group TitleBest ResponseYou've already chosen the best response.2
hmmmm......
 2 years ago

jiteshmeghwal9 Group TitleBest ResponseYou've already chosen the best response.2
u r right sir :) sorry!
 2 years ago

math0101 Group TitleBest ResponseYou've already chosen the best response.0
Excellent answer, satellite73!
 2 years ago

jiteshmeghwal9 Group TitleBest ResponseYou've already chosen the best response.2
@math0101 for steps u can first solve it & prove this wrong or other answer is as @satellite73 sir's answer :)
 2 years ago
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