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anonymous
 3 years ago
√(2x1)=3
Help?
anonymous
 3 years ago
√(2x1)=3 Help?

This Question is Closed

jiteshmeghwal9
 3 years ago
Best ResponseYou've already chosen the best response.2by squaring both sides\[2x1=9\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[\sqrt{2x  1} = 3\] Square on both sides. \[2x  1 = 9\] Quite simple now, can you do it?

jiteshmeghwal9
 3 years ago
Best ResponseYou've already chosen the best response.2solve for 'x' from here

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0don't even start this problem \(\sqrt{2x1}\) is positive, whereas \(3\) is negative, so there is no solution

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0don't square both sides, don't do anything at all a positive number cannot equal a negative one say "no solution" and be done

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0which is good example of making sure you think before you apply some method to a problem

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Hmm... the sqrt(9) isn't 3, but I don't see how that disallows 3^2

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i am assuming you are looking for a real value for \(x\) and not two complex numbers whose square is \(3\)

jiteshmeghwal9
 3 years ago
Best ResponseYou've already chosen the best response.2but @satellite73 sir this gives the condition of the question but he needs to solve for 'x'

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I didn't think from that point of view.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0That was a good point.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Allright, I think I'm getting it. Thanks for all the help. :)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0if so (and i really really doubt it) then this method \[2x1=9\] \[2x=10\] \[x=5\] will certainly not work, and the check is easy \[\sqrt{2\times 51}=\sqrt{9}=3\neq 3\]

jiteshmeghwal9
 3 years ago
Best ResponseYou've already chosen the best response.2u r right sir :) sorry!

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Excellent answer, satellite73!

jiteshmeghwal9
 3 years ago
Best ResponseYou've already chosen the best response.2@math0101 for steps u can first solve it & prove this wrong or other answer is as @satellite73 sir's answer :)
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