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by squaring both sides\[2x-1=9\]

\[\sqrt{2x - 1} = -3\]
Square on both sides.
\[2x - 1 = 9\]
Quite simple now, can you do it?

solve for 'x' from here

which is good example of making sure you think before you apply some method to a problem

Hmm... the sqrt(9) isn't -3, but I don't see how that disallows -3^2

but @satellite73 sir this gives the condition of the question but he needs to solve for 'x'

I didn't think from that point of view.

That was a good point.

Allright, I think I'm getting it. Thanks for all the help. :)

hmmmm......

u r right sir :)
sorry!

Excellent answer, satellite73!