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anonymous
 4 years ago
An infinite charged sheet has a surface charge density of 1 x 10^7 Cm^2 .How far apart are the equipotential surfaces whose potentials differ by 5volts?
anonymous
 4 years ago
An infinite charged sheet has a surface charge density of 1 x 10^7 Cm^2 .How far apart are the equipotential surfaces whose potentials differ by 5volts?

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Work out the electric field at any point, and use the fact that potential energy is \[\int\limits_{\infty}^{a}F(x)dx\](i.e. a unit charge is dragged from infinity, parallel to the field lines, to a)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Use the fact that the electric field is the same everywhere (think of the electric flux through a cylinder on the plane).

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Simpler when the field is constant which it is here  always for infinite plane \[\Delta V = E*\Delta x\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so 5 = E*Delta x find E and then it will help find\[\Delta x\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Yes, basically my integral simplifies to \[U=Fx\] As F is not actually a function of x. Evaluated from infinity to a, or more simply the change in PE (from b to a), yields Mikael's result.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1347905879599:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0@RaphaelFilgueiras pls can you be more legible with ur formulas.....@benpen thanks for the link

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0but the value i get is 8.98 x 10 ^ 4 m @RaphaelFilgueiras any clues

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0it's close my is 8.85x10^4
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