Find the length of the altitude drawn to the hypotenuse. I got to the end and got 105 but do I square root it or leave it as is? Figure is below.

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Find the length of the altitude drawn to the hypotenuse. I got to the end and got 105 but do I square root it or leave it as is? Figure is below.

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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I think you would square root it, not very sure.
I thought the same thing, but I'm not sure as well

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use similar triangles 15 /altitude = altitude / 7 altitude ^ 2 = 7*15 = 105 altitude = sqrt 105
sweetles thanks ^_^
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triangles ABD and ACD are similar
yw

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