cupcake_queen
find the slope of these two pairs. (5,1),(11,1)



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moser90
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dw:1347911846146:dw

moser90
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dw:1347912061405:dw

cupcake_queen
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i got 0/6

moser90
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right but the problem is undefined

moser90
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do you see why?


cupcake_queen
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so if it results with 0 over something its undefined

jazy
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If it results 0 over something the slope is 0.
ex: rise/run .0 rise means it does not rise at all. Its a horizontal line

jazy
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The equation would be y =

cupcake_queen
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0

jazy
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0 is the slope.... there is no slope. Where does the line cross the yaxis?
y = the yintercept

cupcake_queen
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so its undefined

cupcake_queen
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how about if its 2/0

jazy
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No it'd be y = 1 because the line crosses the yaxis at 1.dw:1347913646315:dw

cupcake_queen
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i dont have to graph it

jazy
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That was to help explain what i meant. The equation would be y = 1

cupcake_queen
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why?

jazy
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y = mx + b
m = slope
b = y intercept (where the line crosses the yaxis)
slope = 0 and 1 is the yintercept:
y = 0x + 1
0x = 0
y = 1
That help?

cupcake_queen
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im not using that formula

jazy
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Wait all you need is to find the slope of these two pairs. (5,1),(11,1), right?
Then the slope is 0.

cupcake_queen
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ya

cupcake_queen
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so its not undefined

jazy
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Just remember:
Horizontal line... Slope = 0
Vertical line... Slope = undefined