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cupcake_queen

  • 3 years ago

find the slope of these two pairs. (5,1),(11,1)

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  1. moser90
    • 3 years ago
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    |dw:1347911846146:dw|

  2. moser90
    • 3 years ago
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    |dw:1347912061405:dw|

  3. cupcake_queen
    • 3 years ago
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    i got 0/6

  4. moser90
    • 3 years ago
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    right but the problem is undefined

  5. moser90
    • 3 years ago
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    do you see why?

  6. jazy
    • 3 years ago
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    I responded here(: Let me know if it helped! http://openstudy.com/study#/updates/50578021e4b02986d3714d23

  7. cupcake_queen
    • 3 years ago
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    so if it results with 0 over something its undefined

  8. jazy
    • 3 years ago
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    If it results 0 over something the slope is 0. ex: rise/run .0 rise means it does not rise at all. Its a horizontal line

  9. jazy
    • 3 years ago
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    The equation would be y =

  10. cupcake_queen
    • 3 years ago
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    0

  11. jazy
    • 3 years ago
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    0 is the slope.... there is no slope. Where does the line cross the y-axis? y = the y-intercept

  12. cupcake_queen
    • 3 years ago
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    so its undefined

  13. cupcake_queen
    • 3 years ago
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    how about if its 2/0

  14. jazy
    • 3 years ago
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    No it'd be y = 1 because the line crosses the y-axis at 1.|dw:1347913646315:dw|

  15. cupcake_queen
    • 3 years ago
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    i dont have to graph it

  16. jazy
    • 3 years ago
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    That was to help explain what i meant. The equation would be y = 1

  17. cupcake_queen
    • 3 years ago
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    why?

  18. jazy
    • 3 years ago
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    y = mx + b m = slope b = y -intercept (where the line crosses the y-axis) slope = 0 and 1 is the y-intercept: y = 0x + 1 0x = 0 y = 1 That help?

  19. cupcake_queen
    • 3 years ago
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    im not using that formula

  20. jazy
    • 3 years ago
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    Wait all you need is to find the slope of these two pairs. (5,1),(11,1), right? Then the slope is 0.

  21. cupcake_queen
    • 3 years ago
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    ya

  22. cupcake_queen
    • 3 years ago
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    so its not undefined

  23. jazy
    • 3 years ago
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    Just remember: Horizontal line... Slope = 0 Vertical line... Slope = undefined

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